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julia-pushkina [17]
2 years ago
10

The amount of workers varies inversely with the time, in days, to complete a project. Five workers can complete a certain projec

t in 24 days. How many workers will be needed to complete the project in 15 days?
Mathematics
1 answer:
Feliz [49]2 years ago
6 0

9514 1404 393

Answer:

  8

Step-by-step explanation:

The number of days has gone down by a factor of 15/24. The number of workers is inversely proportional, so must increase by a factor of 24/15 = 8/5.

  (5 workers) × (8/5) = 8 workers

8 workers are needed to complete the project in 15 days.

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We know that each square has a side lenght of 0.1mm

Each unit in the grid represents 0.01mm

Then 10 units in the grid will represent 10*0.01 mm = 0.1mm.

Then the square face will be writen a square with a lenght of 10 units.

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Find the equation in slope-intercept form of a line through (2, 4) with slope 0. Oy=2 Ox=2 Oy=4 0 x = 4​
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If the question is 7 x 200+50+6 it equals 1792
4 0
2 years ago
Brody worked 8.5 hours at Food Lion this week and made $78.20. Based on the number of hours Brody worked and how much he was pai
Lynna [10]

Answer:

1 hour = $9.2

Step-by-step explanation:

The question says that:

Brody makes $78.20 in 8.5 hours.

So,

8.5 hours = $78.20

We need to find 1 hour pay.

So, divide both sides of the above equation by 8.5

8.5 / 8.5 hours = $78.20 / 8.5

1 hour = $9.2

\rule[225]{225}{2}

Hope this helped!

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6 0
2 years ago
Here is a triangular pyramid and its net.
bazaltina [42]

Answer:

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. \text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\

{\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to <em>Lateral Surface Area + Area of base</em>

\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\  mm^{2}

Hence,

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

3 0
3 years ago
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