I need the answer for a= and b=

Interest calculated on a balance every three months is said to be compounded quarterly.

Mariulka [41]

Answer:

True

Step-by-step explanation:

The year is typically divided into equal different lengths of time. There are, for example, quarters, which divide the year by 4, i. e., in 4 periods of 3 months each. Other example are semesters, in this case, the year is divided into 2 periods of 6 months each. Taking this into account, an interest calculated on a balance every three months is compounded quarterly.

3 0

3 years ago

In a card game, a player earns -5 points for each red card drawn. If the player has a score of -20, how many red cards has the p

Margaret [11]

Answer:

4

Step-by-step explanation:

-20/-5=4

7 0

3 years ago

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Simplify 3x³(x+2)+2x(x²+3x)

max2010maxim [7]

Answer:

${3x}^{4} + {8x}^{3} + {6x}^{2}$

Step-by-step explanation:

${3x}^{3} (x + 2) + 2x( {x}^{2} + 3x)$

${3x}^{4} + {6x}^{3} + {2x}^{3} + {6x}^{2}$

${3x}^{4} + {8x}^{3} + {6x}^{2}$

<h3>Hope it is helpful...</h3>

8 0

3 years ago

Which is an estimate of square root of 15 to one decimal place?

Wewaii [24]

3.9 is the estimated square root of 15 to one decimal place

8 0

3 years ago

Read 2 more answers

A drawer contains 3 white shirts, 2 blue shirts, and 5 gray shirts. A shirt is randomly

shutvik [7]

Answer:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

Step-by-step explanation:

Given that

3 white, 2 blue and 5 gray shirts are there.

To find:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = ?

Solution:

Here, total number of shirts = 3+2+5 = 10

First of all, let us learn about the formula of an event E:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(First\ White) = \dfrac{\text{Number of white shirts}}{\text {Total number of shirts left}}$

$P(First\ White) = \dfrac{3}{10}$

Now, this shirt is set aside.

So, total number of shirts left are 9 now.

$P(First\ White\ and\ second\ gray) = P(First White) \times P(Second\ Gray)\\\Rightarrow P(First\ White\ and\ second\ gray) = P(First White) \times \dfrac{\text{Number of gray shirts}}{\text{Total number of shirts left}}\\\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{3}{10} \times \dfrac{5}{9}\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{1}{2} \times \dfrac{1}{2}\\\Rightarrow P(First\ White\ and\ second\ gray) = \bold{\dfrac{1}{4} }$

So, the answer is:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

4 0

3 years ago