It should be C., is that what the graph looks like?
CD bisects angle C, so makes these ratios proportional:
.. AD/AC = BD/BC
.. 3/4 = x/7.5
.. x = 7.5*(3/4) = 5.625
Answer:
0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Step-by-step explanation:
We solve this question working with the probabilities as Venn sets.
I am going to say that:
Event A: Taking a math class.
Event B: Taking an English class.
77% of students are taking a math class
This means that 
74% of student are taking an English class
This means that 
70% of students are taking both
This means that 
Find the probability that a randomly selected student is taking a math class or an English class.
This is
, which is given by:

So

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
Find the probability that a randomly selected student is taking neither a math class nor an English class.
This is

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Step-by-step explanation:
5x+23=0
5x=23
x=23-5
(x=7)
If you multiply 7 * 4 it will give you the number of carnations which is 28.