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Katarina [22]
3 years ago
7

Please help with this question i will mark you brainliest!

Mathematics
1 answer:
adell [148]3 years ago
8 0

9514 1404 393

Answer:

  equation: y = 4x

  graph is attached

Step-by-step explanation:

Let y represent the cost of the peaches in dollars. Let x represent their weight in pounds. Then the relation between the two variables is ...

  cost = (cost per pound) × (pounds)

  y = 4x

__

This graphs as a line through the origin with a slope of 4. In the attached, the x- and y-axes have different scales so more of the graph can be seen.

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Please help!!!!!!!!
Arisa [49]

It should be C., is that what the graph looks like?

6 0
4 years ago
Please help!
alina1380 [7]
CD bisects angle C, so makes these ratios proportional:
.. AD/AC = BD/BC
.. 3/4 = x/7.5
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4 0
3 years ago
Read 2 more answers
In a large school, it was found that 77% of students are taking a math class, 74% of student are taking an English class, and 70
Iteru [2.4K]

Answer:

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

Step-by-step explanation:

We solve this question working with the probabilities as Venn sets.

I am going to say that:

Event A: Taking a math class.

Event B: Taking an English class.

77% of students are taking a math class

This means that P(A) = 0.77

74% of student are taking an English class

This means that P(B) = 0.74

70% of students are taking both

This means that P(A \cap B) = 0.7

Find the probability that a randomly selected student is taking a math class or an English class.

This is P(A \cup B), which is given by:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

So

P(A \cup B) = 0.77 + 0.74 - 0.7 = 0.81

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

Find the probability that a randomly selected student is taking neither a math class nor an English class.

This is

1 - P(A \cup B) = 1 - 0.81 = 0.19

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

6 0
3 years ago
Given the figure below, find the values of x and z<br><br>(5x+23)​
IceJOKER [234]

Step-by-step explanation:

5x+23=0

5x=23

x=23-5

(x=7)

4 0
3 years ago
There were 7 carnations for sale in the store there was four times as many roses as carnations
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If you multiply 7 * 4 it will give you the number of carnations which is 28.
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