Answer:
all work is pictured and shown
To answer the problem given above, divide the difference of the prices by the original price and multiply the answer by 100%. This is,
((22450 - 19450) / 19450) x 100% = 15.42%
Therefore, the percentage markup of the new car is approximately 15.42%.
Answer:12 units^2
Step-by-step explanation:
2*2=4
2*2*1/2=2
2*6*1/2=6
4+2+6=12
12 units^2
Answer:
Pull out like factors
2x + 24 = 2 • (x + 12)
2x + 24 = 2x + 24
This equation is a tautology or an Identity meaning it's always true.
Step-by-step explanation:
Answer:
a) For the 90% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
b) For the 99% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:
Step-by-step explanation:
Previous concepts
The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".
The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.
The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."
Solution to the problem
Part a
For the 90% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
Part b
For the 99% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got: