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3 years ago

When 2x^2-3x+2 is subtracted from 4x^2-5x+2, the result is _____________?

Mathematics

1 answer:

Dennis_Churaev [7]3 years ago

3 0

I think le answer is -2x • (x - 1)

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A farmers land is separated into sections of size 3 5/6 acres. Suppose there are 9 such sections. How many acres of land does th

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Answer: Don't know sorry

Step-by-step explanation:

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2 years ago

Karonlina flips a coin 60 times. how many times would you expect it's to land heads up?

Novosadov [1.4K]

Answer:

30 times

Step-by-step explanation:

There's a 50% chance that they will get heads.

60 divided by 2 is 30

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3 years ago

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Find each percent of change. Round yo the nearest whole percent if necessary. <br><br> 55 to 35

Reptile [31]

So subtract 55 from 35

35 - 55 = -20

then, put -20 over 55

-20/55 equals -0.36 repeating, rounded to -0.36, which equals 36%

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8 0

3 years ago

2+2/50<br> what is the answer?

lozanna [386]

Answer:

2.04

Step-by-step explanation:

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3 years ago

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A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago