Question

The roots of the equation x2 - 14x + 48 = 0) are

Answer 1

Answer:

${x}^{2} - 14x + 48 = 0 \\ {x}^{2} - 6x -8 x + 48 = 0 \\ x(x - 6) - 8(x - 6) = 0 \\ (x - 6)(x - 8) = 0 \\ \boxed{ x = 6\: and \: 8}$

• 4) 6 and 8 is the right answer.