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MAXImum [283]
2 years ago
7

The roots of the equation x2 - 14x + 48 = 0) are

Mathematics
1 answer:
MrRissso [65]2 years ago
5 0

Answer:

{x}^{2}  - 14x + 48 = 0 \\  {x}^{2}  - 6x -8 x + 48 = 0 \\ x(x - 6) - 8(x - 6) = 0 \\ (x - 6)(x - 8) = 0 \\ \boxed{ x = 6\: and \: 8}

  • 4) <em><u>6 and 8</u></em> is the right answer.
You might be interested in
An electric current, I, in amps, is given by I=cos(wt)+√8sin(wt), where w≠0 is a constant. What are the maximum and minimum valu
exis [7]
Take the derivative with respect to t
- w \sin(wt) + \sqrt{8} w cos(wt)
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
0 = -w \sin(wt) + \sqrt{8} w cos(wt)
divide by w
0 =- \sin(wt) + \sqrt{8} cos(wt)
we add sin(wt) to both sides

\sin(wt)= \sqrt{8} cos(wt)
divide both sides by cos(wt)
\frac{sin(wt)}{cos(wt)}= \sqrt{8}   \\  \\ arctan(tan(wt))=arctan( \sqrt{8} ) \\  \\ wt=arctan(2 \sqrt{2)} OR\\ wt=arctan( { \frac{1}{ \sqrt{2} } )
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

I=cos(2n \pi -2arctan( \sqrt{2} ))
since 2npi is just the period of cos
cos(2arctan( \sqrt{2} ))= \frac{-1}{3} &#10;
substituting our second soultion we get
I=cos(2n \pi +2arctan( \frac{1}{ \sqrt{2} } ))
since 2npi is the period
I=cos(2arctan( \frac{1}{ \sqrt{2}} ))= \frac{1}{3}
so the maximum value =\frac{1}{3}
minimum value =- \frac{1}{3}


4 0
3 years ago
Could someone help me complete this chart? It’s kinda confusing.
NARA [144]

Answer:

1. - completed

2. expanded = a · a · a · a

3. base = a | exponent = 5 | expanded = a · a · a · a · a

4. - completed

5. base = c | exponent = 3 | expanded = c · c · c

6. base = c | exponent = 4 | expanded = c · c · c · c

7. base = m | exponent = 2 | expanded = m · m

8. base = m | exponent = 3 | expanded = m · m · m

9. power = y⁵ | base = y | exponent = 5

10. power = y⁸ | expanded = y · y · y · y · y · y · y · y

hope this helps ! brainliest ?

3 0
3 years ago
Una pared rectangular tiene un perímetro de 48 metros. El largo de la pared es el doble del ancho. ¿Cuántos metros cuadrados de
AveGali [126]
Datos:
Perímetro = 48m
Ancho = x
Largo = 2x
Área = (2x)(x)

Ecuación:
2x + 4x = 48
6x = 48
x = 48/6
x = 8

Sustitución:
Área = [2(8)](8)
Área = (16)(8)
Área = 128

Respuesta: Se necesitarán 128 metros cuadrados de papel decorativo
4 0
2 years ago
Please help me ill mark you brainiest
Ann [662]

Answer:

55.560

Step-by-step explanation:

I imputed the equation in my calculator

5 0
3 years ago
I need to know how to make the equations
Bogdan [553]
Asked and answered elsewhere.
brainly.com/question/9016540
3 0
3 years ago
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