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2 years ago

What is the image point of (-7,7) after a translation right 1 unit and down 3 units?

Mathematics

1 answer:

ZanzabumX [31]2 years ago

6 0

Answer:

(-6, 4)

Step-by-step explanation

translation rule: (x+1,y-3)

(-7+1, 7-3)

(-6, 4)

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Q’R’S’ is the image of QRS under a dilation through point C. What scale factor was used in the dilation?

ad-work [718]

-4 i believe is the answer

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3 years ago

Read 2 more answers

Seven subtracted from c is less then -18: translate into an inequality

777dan777 [17]

Answer:

c - 7 < -18

Step-by-step explanation:

Seven subtracted from c : c - 7

c - 7 < -18

3 0

3 years ago

Consider f and c below. f(x, y) = x2 i + y2 j c is the arc of the parabola y = 2x2 from (−1, 2) to (1, 2) (a) find a function f

Korvikt [17]

If there is some scalar function $f(x,y)$ such that

$\nabla f(x,y)=\mathbf f(x,y)=x^2\,\mathbf i+y^2\,\mathbf j$

then we want to find $f$ such that

$\dfrac{\partial f}{\partial x}=x^2\implies f(x,y)=\dfrac{x^3}3+g(y)$
$\dfrac{\partial f}{\partial y}=y^2=\dfrac{\mathrm dg}{\mathrm dy}\implies g(y)=\dfrac{y^3}3+C$
$\implies f(x,y)=\dfrac{x^3}3+\dfrac{y^3}3+C$

So the vector field $\mathbf f(x,y)$ is conservative, which means the fundamental theorem applies; the line integral of $\mathbf f$ along any path $\mathcal C$ parameterized by some vector-valued function $\mathbf r(t)$ over $a\le t\le b$ is given by

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=a}^{t=b}\mathbf f(\mathbf r(t))\cdot\dfrac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt=f(\mathbf r(b))-f(\mathbf r(a))$

In this case,

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f(1,2)-f(-1,2)=\dfrac23$

5 0

2 years ago

What is the value of the expression 2^2 + 4^2 ÷ 2^2?

Dennis_Churaev [7]

Answer:

The answer is C.

Hope this helped!!

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3 years ago

What can you add to get 48 but subtract to get 13

agasfer [191]

Answer:

30 or 20 something

Step-by-step explanation:

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3 years ago