Ratio is 5girls:7boys with total 72 students
5+7= 12
72➗12= 6
6(5:7)= 30 girls : 42 boys
New ratio is 3:4 with 48 boys
48➗4= 12
So for girls 3x12= 36
So started with 30 girls ended with 36 girls... 6 girls joined band during the school year.
The radii of the frustrum bases is 12
Step-by-step explanation:
In the figure attached below, ABC represents the cone cross-section while the BCDE represents frustum cross-section
As given in the figure radius and height of the cone are 9 and 12 respectively
Similarly, the height of the frustum is 4
Hence the height of the complete cone= 4+12= 16 (height of frustum+ height of cone)
We can see that ΔABC is similar to ΔADE
Using the similarity theorem
AC/AE=BC/DE
Substituting the values
12/16=9/DE
∴ DE= 16*9/12= 12
Hence the radii of the frustum is 12
Your diagram is correct.
I would have however written the Given as stated
Given :
XB≅XA≅AY≅YB ( If they are equidistant then they are all the same distance, thus the values will all be equal)
Prove:
<x≅<b≅<y≅<a (this is because a square is formed) < is angle
XM≅YM≅AM≅MB (The fact that the previous statements are true means that this is a square, if M is the midpoint than all these segments are equal)
MX≅MY
Im not sure what you did wrong besides maybe you didn't prove it well enough, everything is correct that you have written. I cant read the pen but it looks like you were missing a step.
The answer is 29, because i did long division on a paper i can not show the work.
Answer: Yes it does represent a dilation... It is enlarged..
Step-by-step explanation:
