Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.
Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A
Applying that here:
40^2 = 32^2 + 64^2 - 2(32)(64)cos Q
Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.
Answer:
Substitute the x and y values from the ordered pairs into the equation, one by one, until both sides of the equation are equal.
Step-by-step explanation:
A. (-2,-3)
3 * (-2) - 4 * (-3) = 21
-6 + 12 = 21
6 = 21 <u>not equal</u>
B. (0,7)
3 * 0 - 4 * 7 = 21
0 - 28 = 21
- 28 = 21 <u>n</u><u>o</u><u>t</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>l</u>
C. (7,0)
3 * 7 - 4 * 0 = 21
21 - 0 = 21
21 = 21 <u>equal</u>
Answer:
no they don't
Step-by-step explanation:
leah has a higher goal-assist ratio with 1 more assist than maddie
Sqrt(27)+sqrt(48)+sqrt(12)
Sqrt(27)=sqrt(3*3*3)=3*sqrt(3)
Sqrt(48)=sqrt(4*4*3)=4*sqrt(3)
Sqrt(12)=sqrt(2*2*3)=2*sqrt(3)
Add the three to get 9*sqrt(3)
Final answer:
9*sqrt(3)
Hope I helped :)
-7 - (5.x) = 28? Is that what you were looking for?
