Use the trig identity
2*sin(A)*cos(A) = sin(2*A)
to get
sin(A)*cos(A) = (1/2)*sin(2*A)
So to find the max of sin(A)*cos(A), we can find the max of (1/2)*sin(2*A)
It turns out that sin(x) maxes out at 1 where x can be any expression you want. In this case, x = 2*A.
So (1/2)*sin(2*A) maxes out at (1/2)*1 = 1/2 = 0.5
The greatest value of sin(A)*cos(A) is 1/2 = 0.5
Answer: how many hours is she working
Step-by-step explanation:
Answer:
what is the side, length, and width
Step-by-step explanation:
Answer:
300 miles
Step-by-step explanation:
The distance equation is D = RT
Where
D is the distance
R is the rate
T is the time
<u>Mindy</u>
8 am to 1 pm = 5 hours
<u>Kelly</u>
8 am to 2 pm = 6 hours
Kelly's rate is 10 mph SLOWER than mindy, so if we let Mindy's rate be "m", so Kelly's rate will be " m - 10 "
Now using the distance equation, we can write:
Mindy >>> D = RT >>> D = 5m
Kelly >>> D = RT >>> D = 6(m-10) >>> D = 6m - 60
Since both the distances are equal, we can write:
5m = 6m - 60
m = 60
We want the distance, we know:
D = 5m
D = 5(60)
D = 300 miles
The distance is 300 miles
