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Assoli18 [71]
3 years ago
5

B4.1a) The diagram shows a triangle.

Mathematics
1 answer:
Yuki888 [10]3 years ago
3 0
So angles on a straight line add up to 180°
And angles in a triangle adds up to 180° try if you can work it out now
If you still don’t understand let me know
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Exercise 3.5. For each of the following functions determine the inverse image of T = {x ∈ R : 0 ≤ [x^2 − 25}.
masya89 [10]

a. The inverse image of f(x) is f⁻¹(x) = ∛(x/3)

b. The inverse image of g(x) is g^{-1}(x) = e^{x}

c. The inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

<h3 /><h3>The domain of T</h3>

Since T = {x ∈ R : 0 ≤ [x^2 − 25} ⇒ x² - 25 ≥ 0

⇒ x² ≥ 25

⇒ x ≥ ±5

⇒ -5 ≤ x ≤ 5.

<h3>Inverse image of f(x)</h3>

The inverse image of f(x) is f⁻¹(x) = ∛(x/3)

f : R → R defined by f(x) = 3x³

Let f(x) = y.

So, y = 3x³

Dividing through by 3, we have

y/3 = x³

Taking cube root of both sides, we have

x = ∛(y/3)

Replacing y with x we have

y = ∛(x/3)

Replacing y with f⁻¹(x), we have

So,  the inverse image of f(x) is f⁻¹(x) = ∛(x/3)

<h3>Inverse image of g(x)</h3>

The inverse image of g(x) is g^{-1}(x) = e^{x}

g : R+ → R defined by g(x) = ln(x).

Let g(x) = y

y =  ln(x)

Taking exponents of both sides, we have

e^{y} = e^{lnx} \\e^{y} = x

Replacing x with y, we have

y = e^{x}

Replacing y with g⁻¹(x), we have

So, the inverse image of g(x) is g^{-1}(x) = e^{x}

<h3>Inverse image of h(x)</h3>

The inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

h : R → R defined by h(x) = x − 9

Let y = h(x)

y = x - 9

Adding 9 to both sides, we have

y + 9 = x

Replacing x with y, we have

x + 9 = y

Replacing y with h⁻¹(x), we have

So, the inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

Learn more about inverse image of a function here:

brainly.com/question/9028678

5 0
2 years ago
Of all the soft drink consumers in a particular sales region, 30% prefer Brand A and 70% prefer Brand
victus00 [196]

Answer:

Option D -0.67

Step-by-step explanation:

Given : Preference of Brand A =30% ⇒ P(A)=\frac{30}{100}=0.3

Preference of Brand B =70% ⇒ P(B)=\frac{70}{100}=0.7

Prefer Brand A and are Female = 20% ⇒ P(A/F)=\frac{20}{100}=0.2

Prefer Brand B and are Female = 40% ⇒ P(B/F)=\frac{40}{100}=0.4

To find : Selected consumer is female, given that the person prefers Brand A P(F/A)

Solution : Using Bayes' theorem, which state that

P(A/B)=\frac{P(B/A)P(A)}{P(B)}

where, P(A) and P(B) are probabilities of observing A and B.

P(B/A)= is a conditional probability where event B occur and A is true

P(A/B)= also a conditional probability where event A occur and B is true.

Now, applying Bayes' theorem,

P(F/A)=\frac{P(A/F)P(A)}{P(B)P(B/F)+P(A)P(A/F)}

P(F/A)=\frac{(0.2)(0.3)}{(0.7)(0.4)+(0.3)(0.2)}

P(F/A)=\frac{0.6}{0.28+0.6}

P(F/A)=\frac{0.6}{0.88}

P(F/A)=0.68

Therefore, Option D is correct probability that a randomly selected consumer is female, given that the person prefers Brand A -0.67

3 0
3 years ago
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A line segment that has one endpoint at the center of a circle and the other endpoint on the circle?
Umnica [9.8K]
What's the actual question? That's the same as the radius of the circle if that's what you're asking
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Answer:

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Step-by-step explanation:

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Anyone know how to complete this table need helpp asapp please
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Answer:

Step-by-step explanation:

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8 0
3 years ago
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