Answer:
area of the BCD triangle=1/2×10×9
=45
area of the ABD triangle=1/2×10×3
=15
Total area=45+15
=60 square centimetres
Sixth grade:
7 | x x x x x x
8 | x x x x
9 |x x x x x x
A | x x x x . . . . . . . . where "A" is used to represent 10 tens (100)
7th grade:
5 | x x x x x
6 | x x x x x x x
7 | x x x x
8 | x x x x
The range (low, high) and median of the 6th grade scores are all higher than those of the 7th grade scores.
Based on visual inspection, Grade 6 appears to have the higher mean score.
We need to find the area. So we multiply the dimensions.
3x1/2=1.5
1.5x4 1/2=6.75
Decimal was my go-to so we need to convert back to a fraction.
6.75= 6 3/4
So the answer is B.
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hope it helps
The correct answer is 6/7.
Answer:
Yes, the given measures can be the lengths of the sides of a triangle.
Step-by-step explanation:
hope this helps
