D(t)=-16t²+32t+88
a] Maximum height
At maximum height d'(t)=0
from d(t);
d'(t)=-32t+32=0
thus
t=1
hence the maximum height will be:
d(t)=-16t²+32t+88
d(1)=-16(1)^2+32(1)+88
d(1)=104 ft
2] <span> how many seconds does it take to reach the ground after first being thrown upward?
Here we solve for t intercept
</span>when d(t)=0
<span>thus</span>
0=-16t²+32t+88
<span>solving for t, we get:
t=1-</span>√13/2
or
<span>t=1+</span>√13/2
<span>
t=-1.55 or t=3.55 sec
Thus the answer is t=3.55 sec
</span>
Answer:
The chosen topic is not meant for use with this type of problem. Try the examples below.
27x4−x
x2−81
x2+12x+36
Step-by-step explanation:
Answer:
you must make an equation
Step-by-step explanation:
if you make an equation you should get the answer
Answer:
20%
Step-by-step explanation:
If you see they say that the number decreased is 10% each and they say it two times. we could see that the missing number is as big as the length of two 10% together, so if you add them two you get 20%.
