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FinnZ [79.3K]
3 years ago
6

A politician claims that a proposal for a new traffic law is broadly supported by both political parties and that a person from

either political party is equally likely to support the proposed legislation. He cites two recent polls that said 70% of a random sample of 550 people from his political party supports the law, and 65% of a random sample of 420 people from the other political party supports the law. The 95 percent confidence interval for the difference in population proportions is (–0.010, 0.110). Based on the interval, is the politician’s claim justified?
Mathematics
1 answer:
Mashutka [201]3 years ago
4 0

Answer:

Based on the 95% confidence interval for the difference in population proportion, there is convincing statistical evidence that he is correct

Step-by-step explanation:

The proportion from the sample of people from his party that support the law = 70%

The number the members of the politicians political party that support the law = 550 people

The proportion from the sample of people from the other party that support the law = 65%

The number the members of the politicians political party that support the law = 420 people

The confidence level of the test = 95%

The given confidence interval for the difference in proportion, C.I. = (-0.010, 0.110)

Given that the 95% confidence interval for the difference in population proportion ranges from -0.010, to 0.110, it is 95% certain that 0 is among the likely difference in proportion between the two populations and therefore, there is sufficient statistical evidence to suggest that there is no difference in the proportion of the members of either political that support the proposed new traffic law.

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Step-by-step explanation:

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Express the confidence interval 0.555 less than 0.777 in the form Modifying above p with caret plus or minus Upper E.
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Complete Question

Express the confidence interval 0.555 less than p less than  0.777 in the form Modifying above p with caret plus or minus Upper E.

Answer:

The modified representation is \r p \pm  E  = 0.666 \pm  0.111

Step-by-step explanation:

From the question we are told that

    The  confidence interval interval is  0.555 <  p <  0.777

Now looking at the values that make up  the up confidence interval we see that this is a symmetric  confidence interval(This because the interval covers 95%  of the area under the normal curve which mean that the probability of a value falling outside the interval is 0.05 which is divided into two , the first half on the left -tail and the second half on the right tail  as shown on the figure in the first uploaded image(reference - Yale University ) ) which means

     Now  since the confidence interval is  symmetric , we can obtain the sample proportion as follows

             \r p  =  \frac{0.555 + 0.777}{2}

            \r p  =0.666

Generally the margin of error is mathematically represented as

            E  =  \frac{1}{2}  *  K

Where  K is the length of the confidence interval which iis mathematically represented as

           K  =  0.777 -0.555

         K  = 0.222

Hence  

          ME  =  \frac{1}{2}  *  0.222

           ME  =  0.111

So the confidence interval can now be represented as

        \r p \pm  E  = 0.666 \pm  0.111

     

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