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prisoha [69]
3 years ago
8

An arrow is shot vertically upward from a platform 19ft high at a rate of 163ft/sec. When will the arrow hit the ground? Use the

formula: h=−16t2+v0t+h0. (Round your answer to the nearest tenth.)
Mathematics
1 answer:
Triss [41]3 years ago
7 0

Answer: 10.3 s

Step-by-step explanation:

Given

The height of the arrow is given by h=-16t^2+v_ot+h_o

At  t=0, h=19\ ftand v_o=163\ ft/s

When arrow hits ground, h becomes 0 i.e.

\Rightarrow 0=-16t^2+163t+19\\\Rightarrow 16t^2-163t-19=0\\\\\Rightarrow t=\dfrac{163\pm \sqrt{(-163)^2+4(16)(19)}}{2(16)}\\\\\Rightarrow t=-0.115,10.30\ s

Neglecting the negative value of t

So, the arrow hits the ground after 10.30 s

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