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SCORPION-xisa [38]
3 years ago
7

In a school, the number of boys is 9 more than thrice the

Mathematics
2 answers:
adoni [48]3 years ago
7 0

Let the number of girls = x

Then, According to the question,

number of the boys = 9 + 3x9+3x

Total students in class = 60, so

\begin{gathered}9 + 3x + x = 60 \\ = > 9 + 4x = 60 \\ = > 4x = 60 - 9 \\ = > 4x = 51 \\ = > x = 51 \div 4 \\ = > x = 12.75\end{gathered}9+3x+x=60=>9+4x=60=>4x=60−9=>4x=51=>x=51÷4=>x=12.75

On rounding off

Then, number of girls = 13

SCORPION-xisa [38]3 years ago
3 0

\huge\underline{\overline{\mid{\bold{\red{ANSWER}}\mid}}}

Let the number of girls = x

Then, According to the question,

number of the boys = 9 + 3x

Total students in class = 60, so

9  + 3x + x = 60 \\  =  > 9 + 4x = 60 \\  =  > 4x = 60 - 9 \\  =  > 4x = 51 \\  =  > x = 51 \div 4 \\  =  > x = 12.75

On rounding off

Then, number of girls = 13

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finlep [7]

Answer:

30% is the correct answer.

Step-by-step explanation:

Total number of boys = 2

Total number of girls = 3

Total number of students = 5

To find:

Probability that the pianist will be a boy and the alternate will be a girl?

Solution:

Here we have to make 2 choices.

1st choice has to be boy (pianist) and 2nd choice has to be girl (alternate).

\bold{\text{Required probability }= P(\text{boy as pianist first}) \times P(\text{girl as alternate})}

Formula for probability of an event E is given as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

For P(\text{boy as pianist}), number of favorable cases are 2 (total number of boys).

Total number of cases = Total number of students i.e. 5

So, P(\text{boy as pianist}) is:

P(\text{boy as pianist}) = \dfrac{2}{5}

For P(\text{girl as alternate}), number of favorable cases are 3 (total number of girls).

Now, one boy is already chosen as pianist so Total number of cases = Total number of students left i.e. (5 - 1) = 4

P(\text{girl as alternate}) = \dfrac{3}{4}

So, the required probability is:

\text{Required probability } = \dfrac{2}{5}\times \dfrac{3}{4} = \dfrac{3}{10} = \bold{30\%}

6 0
3 years ago
Find the value of k such that lim-->4 (x^2+x-k)/(x-4) exists
7nadin3 [17]

Answer:

k=20

Step-by-step explanation:

when x approaches 4, the denominator x-4 approaches 0

if the denominator is 0, it means that this is invalid

if the function is a number over 0 when x=4, it represents a vertical asymptote, which means no limit

so the only way possible to let there be a limit is to let the function be 0/0 when we plug in x=4

so x^2 + x - k = 0 when x = 4

4^2 + 4 - k = 0 ==> 20 - k = 0 ==> k = 20

6 0
2 years ago
Which of the following points are more than 5 units from the point P(−2, −2)? Select all that apply. A A (2, 1) B B (4, −1) C C
netineya [11]

The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:<span>

<span> |PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}}</span></span>


Using this formula we calculate the distances |PA|, |PB|, |PC|, |PD| and |PE| and compare to 5.


|PA|= \sqrt{ (-2-2)^{2} + (-2-1)^{2}}= \sqrt{16+9}= \sqrt{25}=5

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|PC|= \sqrt{ (-2-2)^{2} + (-2+3)^{2}}= \sqrt{16+1}= \sqrt{17}\approx4

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Answer: B and D





3 0
3 years ago
|6m−2|=0 please help
Deffense [45]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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For proportionality constant problems, set up the equation as,

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45=K(30)\\K=\frac{45}{30}= \frac{3}{2}.

Hence, the proportionality constant, in this case <em>K,</em> is equal to \frac{3}{2} or 1.5. First answer choice is correct.


ANSWER: 1.5


4 0
3 years ago
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