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7nadin3 [17]
3 years ago
13

Solve the inequality 2x - 3 < x 2 ≤ 3x 5. show your work

Mathematics
2 answers:
Digiron [165]3 years ago
8 0
<span>2x − 3 < x + 2  </span>
<span>∴ x − 3 < 2  </span>
<span>∴ x < 5 </span>

<span>x + 2 ≤ 3x + 5 </span>
<span>∴ 2 ≤ 2x + 5 </span>
<span>∴ -3 ≤ 2x </span>
<span>∴ -3/2 ≤ x </span>

<span>-3/2 ≤ x < 5</span>
Alexxx [7]3 years ago
3 0

Answer:

-3/2 ≤ x < 5  

Step-by-step explanation:

2x - 3 < x + 2 ≤ 3x+5

Solve the inequality separately

2x-3 <x+2  and x+2≤ 3x+5

LEts solve one by one

2x-3 <x+2

Subtract x from both sides

x -3 < 2

add 3 on both sides

x< 5

x+2≤ 3x+5

Subtract 3x from both sides

-2x + 2 ≤ 5

Subtract 2 from both sides

-2x ≤  3

Divide both sides by -2

x ≥ -3/2

we got x>= -3/2 and x<5

so x lies between -3/2  and 5

-3/2 ≤ x < 5

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Answer:

4x

Step-by-step explanation:

So what you wanna do is look everywhere a point is on a line perfectly. Then see how much it takes per point that's on a line perfectly

8 0
3 years ago
What is the interquartile range of the data set ​
Verizon [17]

There are many methods of doing this. This one finds the median; however, instead of halving, you can use quarters instead.

First order the data, ascendingly:

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Find the median:

For an even number of values: The number of values / 2

For an odd number of values: The number of values + 1 / 2

11 is odd.

11 + 1 / 2

12 / 2 = 6

The median is at the 6th position.

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

The median is 20.

<em>Other method:</em>

<em>You don't need this step.</em>

Using the values lower than the median, exclusive, find the median of the lower values;

For an odd number of values: <u>The number of values + 1 / 2</u>

10, 17, 18, 18, 18

5 + 1 / 2 = 6 / 2 = 3

The median of the lower values is at position 3.

This is the lower quartile.

10, 17, 18, 18, 18

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>The number of values + 1 / 4</em></u>

<em>11 + 1 / 4 = 12 / 4 = 3</em>

<em>10, 17, </em><em>18,</em><em> 18, 18, 20, 20, 25, 25, 30, 30</em>

<em />

Using the values greater than the median, exclusive, find the median:

For an odd number of values: <u>The number of values + 1 / 2</u>

20, 25, 25, 30, 30

5 + 1 / 2 = 6 / 2 = 3

The median of the upper values is at position 3.

20, 25, 25, 30, 30

This is 25.

This is the upper quartile.

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>(The number of values + 1 / 4) * 3</em></u>

<em>(11 + 1 / 4) * 3 = (12 / 4)  * 3 = 3 * 3 = 9</em>

<em>10, 17, 18</em><em>,</em><em> 18, 18, 20, 20, 25, </em><em>25</em><em>, 30, 30</em>

Your interquartile range is 3 - 25

25 - 3 = 21

<h2>21</h2>
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6 0
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Read 2 more answers
According to the manufacturer of the candy Skittles, 20% of the candy produced are red. If we take a random sample of 100 bags o
WITCHER [35]

Answer:

0.15651

Step-by-step explanation:

This can be approximated using a Poisson distribution formula.

The Poisson distribution formula is given by

P(X = x) = (e^-λ)(λˣ)/x!

P(X ≤ x) = Σ (e^-λ)(λˣ)/x! (Summation From 0 to x)

where λ = mean of distribution = 20 red bags of skittles (20% of 100 bags of skittles means 20 red bags of skittles)

x = variable whose probability is required = less than 16 red bags of skittles

P(X < x) = Σ (e^-λ)(λˣ)/x! (Summation From 0 to (x-1))

P(X < 16) = Σ (e^-λ)(λˣ)/x! (Summation From x=0 to x=15)

P(X < 16) = P(X=0) + P(X=1) + P(X=2) +......+ P(X=15)

Solving this,

P(X < 16) = 0.15651

4 0
3 years ago
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