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7nadin3 [17]
4 years ago
13

Solve the inequality 2x - 3 < x 2 ≤ 3x 5. show your work

Mathematics
2 answers:
Digiron [165]4 years ago
8 0
<span>2x − 3 < x + 2  </span>
<span>∴ x − 3 < 2  </span>
<span>∴ x < 5 </span>

<span>x + 2 ≤ 3x + 5 </span>
<span>∴ 2 ≤ 2x + 5 </span>
<span>∴ -3 ≤ 2x </span>
<span>∴ -3/2 ≤ x </span>

<span>-3/2 ≤ x < 5</span>
Alexxx [7]4 years ago
3 0

Answer:

-3/2 ≤ x < 5  

Step-by-step explanation:

2x - 3 < x + 2 ≤ 3x+5

Solve the inequality separately

2x-3 <x+2  and x+2≤ 3x+5

LEts solve one by one

2x-3 <x+2

Subtract x from both sides

x -3 < 2

add 3 on both sides

x< 5

x+2≤ 3x+5

Subtract 3x from both sides

-2x + 2 ≤ 5

Subtract 2 from both sides

-2x ≤  3

Divide both sides by -2

x ≥ -3/2

we got x>= -3/2 and x<5

so x lies between -3/2  and 5

-3/2 ≤ x < 5

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Two semicircles are attached to the sides of a rectangle as shown.
melomori [17]

Answer:

157\ in^{2}

Step-by-step explanation:

we know that

The area of the figure is equal to the area of rectangle plus the area of two semicircles

<u>The area of rectangle is equal to</u>

A=14*5=70\ in^{2}

<u>The area of the small semicircle is equal to</u>

A=\pi r^{2} /2

r=5/2=2.5\ in -----> radius is half the diameter

substitute

A=(3.14)(2.5^{2})/2=9.8125 in^{2}

<u>The area of the larger semicircle is equal to</u>

A=\pi r^{2} /2

r=14/2=7\ in -----> radius is half the diameter

substitute

A=(3.14)(7^{2})/2=76.93\ in^{2}

The area of the figure is equal to

70+9.8125+76.93=156.7425=157\ in^{2}

8 0
3 years ago
Read 2 more answers
PLEASE HELP FAST!
Flura [38]
2² · 3³ · 5 · 7
Is the answer and the lowest common multiple is 1260.

Hope this helps :)
6 0
3 years ago
If the fraction 414/x-10 is equivalent to -23 ​, find the value of x. Show your work. Use reasoning to find x.
NemiM [27]

Answer:

x = -8

Step-by-step explanation:

Solve for x by getting rid of the fraction.

414/(x-10) = -23

414 = -23(x-10)

414 = -23x + 230

184 = -23x

-8 = x

4 0
3 years ago
The sum of the measures of the angles of any triangle is 180°. In triangle ABC, angles A and B have the same measure, while the
lesya [120]

This is the solution

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4 0
3 years ago
Show that X^2-8x+20 can be written in the form (x-a)^2+a
svlad2 [7]

Answer:x^2 + 8x + 20

a = 1

b = 8

c = 20

Discriminant = b^2 - 4ac

=> 8^2 - 4(1)(20)

=> 64 - 80

=> -16

As -16<0

So, equation has no real roots

I hope this will help you

(-:

Step-by-step explanation:

8 0
3 years ago
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