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3 years ago

7.5 as an improper fraction in its simplest form

Mathematics

1 answer:

bezimeni [28]3 years ago

3 0

Answer:

7.5 as an improper fraction in its simplest form would be 15/2

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11.05 divided by 10.5

Sonbull [250]

1.05(2380..)
ps: i might be wrong

4 0

3 years ago

Nola was selling tickets at the high school dance. At the end of the evening, she picked up the cash box and noticed a dollar ly

Black_prince [1.1K]

Answer:

yes

Step-by-step explanation:

s + 2c = 47

5s+8c = 200

which one checks as in the other solution does not have a solution in non-negative integers. On the other hand, the analogous system

s + 2c = 47

5s+8c = 201

with solution s=13 and c=17. So, as in the other solution, we conclude that the extra dollar belongs in the cash box, with 13 singles and 17 couples attending the dance.

5 0

3 years ago

Given f(x)=x-7 and h(x)=2x+3 write the rule for f(h(x))

cestrela7 [59]

Step-by-step explanation:

f(x)=x-7&h(x)=2x+3 then fohx)=2x-4

6 0

3 years ago

Plz help the question is so confusing!!

gizmo_the_mogwai [7]

Answer:

-2

Step-by-step explanation:

because the slope is 2, a perpendicular line must be the inverse

the equation for y1 is y=2x+1

y2= -2y+1

5 0

3 years ago

Read 2 more answers

Do the points (−1,9) and (2,4) represent the vertex and a sample point, respectively, of y=−2(x+1)2+9? Explain

Reil [10]

Answer:

Vertex: (-1,9) is true

Sample Points: (2,4) is not true

Step-by-step explanation:

Given

$Vertex: (-1,9)$

$Sample\ Points: (2,4)$

Required

Determine if the vertex and sample points exist for $y= -2(x+1)\²+9$

Solving for the vertex:

$y= -2(x+1)\²+9$

Writing the given equation in the form:

$y = ax^2 + bx + c$

Expand the bracket

$y= -2(x+1)(x+1)+9$

Open Bracket

$y= -2(x+1)(x+1)+9$

$y = -2(x^2 + 2x + 1) + 9$

Open bracket

$y = -2x^2 - 4x -2 + 9$

$y = -2x^2 - 4x +7$

Solve for x using:

$x = \frac{-b}{2a}$

Where $a = -2$ ; $b = -4;$

So:

$x = \frac{-(-4)}{2 * (-2)}$

$x = \frac{4}{-4}$

$x = -1$

Substitute -1 for x in $y = -2x^2 - 4x +7$

$y = -2(-1)^2 -4(-1) + 7$

Simplify all brackets

$y = -2(1) + 4 + 7$

$y = -2 + 4 + 7$

$y = 9$

Hence;

The vertex (x,y) is (-1,9)

This is true

Checking sample points: $(2,4)$

In this case; $x = 2$ and $y = 4$

Substitute $x = 2$ and $y = 4$ in $y= -2(x+1)\²+9$

$4 = -2(2 + 1)^2 + 9$

$4 = -2(3)^2 + 9$

$4 = -2 * 9 + 9$

$4 = -18 + 9$

$4 \neq -9$

Hence;

This sample points  $(2,4)$  does not exist

8 0

3 years ago