# of ways to select 3 defective:: 3C3 = 1
----
# of random sets of 3:: 12C3 = (12*11*10)/(1*2*3) = 220
----
P(3 defective) = 1/220
16 I think................
Answer:
10x-20
Step-by-step explanation:
Not sure if it's right but I tried:
(16,-12) assuming x=16,y=-12
y=5x-4
-12=5(16)-4
-12=240-4
-12=236
(Divide maybe?)
-12=236
236 divided 12= 19.6
