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Elenna [48]
3 years ago
14

Find x using the secant-tangent theorem.

Mathematics
1 answer:
zepelin [54]3 years ago
4 0

Answer:

Step-by-step explanation:

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How many ways can two students be chosen from a group of four?<br><br> 4<br> 6<br> 14<br> 10
taurus [48]

Answer:

6

Step-by-step explanation:

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Does anyone know how to turn these fractions into percents??? please help!!!
belka [17]
You divide the fractions to get percents
4 0
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Waylon played defense in 12 soccer games. This was 60% of the total games he played. How many games did Waylon play?
puteri [66]

Answer:

20 games

Step-by-step explanation:

(12/x)=(60/100)

12*100=1200

60x=1200

x=20

4 0
3 years ago
What are the values of x ?
Vera_Pavlovna [14]

Answer:

50

Step-by-step explanation:

since they are parallel then 2x+6=106

so subtract 6 from each side so it's 2x = 100

then divide each since by 2

so x= 50

7 0
3 years ago
Read 2 more answers
Birth weights at a local hospital have a Normal distribution with a mean of 110 oz and a standard deviation of 15 oz. The propor
OLga [1]

Answer:

The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 110, \sigma = 0.15

The proportion of infants with birth weights between 125 oz and 140 oz is

This is the pvalue of Z when X = 140 subtracted by the pvalue of Z when X = 125. So

X = 140

Z = \frac{X - \mu}{\sigma}

Z = \frac{140 - 110}{15}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 125

Z = \frac{X - \mu}{\sigma}

Z = \frac{125 - 110}{15}

Z = 1

Z = 1 has a pvalue of 0.8413

0.9772 - 0.8413 = 0.1359

The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.

4 0
3 years ago
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