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3 years ago

Can anyone answer this ASAP

Mathematics

1 answer:

irga5000 [103]3 years ago

4 0

Answer:

68in^2

Step-by-step explanation:

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Use a table of values to estimate the value of the limit. Confirm your result graphically by graphing the function with a graphi

il63 [147K]

Hello,

$\lim_{x \to 0}\dfrac{ \sqrt{x+25}-5}{x}\\\\$

$=\lim_{x \to 0}\dfrac{(\sqrt{x+25}-5)*(\sqrt{x+25}+5)}{x*(\sqrt{x+25}+5)}\\\\$

$=\lim_{x \to 0}\dfrac{x+25-25)}{x*(\sqrt{x+25}+5)}\\\\$

$=\dfrac{1}{10}$

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3 years ago

There are 8 competitors in each ring for a tae kwon do tournament. If there are 96 competitors in the tournament, how many rings

Marysya12 [62]

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3 years ago

Read 2 more answers

solve the system of equations below by graphing both equations with a pencil and paper. what is the solution y = x - 1 y = 1/2x

Elan Coil [88]

Answer:

(4,3)

Step-by-step explanation:

$(x-1) = \frac{1}{2}x +1$

$(x-\frac{1}{2}x)-(-1+1)=(\frac{1}{2}x-\frac{1}{2}x)+(1+1)$

$(\frac{1}{2}x/\frac{1}{2})=(2/\frac{1}{2})$

$x=4$

$y=(4)-1$

$y=3$

$y=\frac{1}{2}(4)+1$

$y=2+1$

$y=3$

6 0

3 years ago

ASAP!!!!!! Y-9=4(X+2)

Artemon [7]

SimplifyingY + -9 = 4(x + -2)
Reorder the terms:-9 + Y = 4(x + -2)
Reorder the terms:-9 + Y = 4(-2 + x)-9 + Y = (-2 * 4 + x * 4)-9 + Y = (-8 + 4x)
Solving-9 + Y = -8 + 4x
Solving for variable 'Y'.
Move all terms containing Y to the left, all other terms to the right.
Add '9' to each side of the equation.-9 + 9 + Y = -8 + 9 + 4x
Combine like terms: -9 + 9 = 00 + Y = -8 + 9 + 4xY = -8 + 9 + 4x
Combine like terms: -8 + 9 = 1Y = 1 + 4x
SimplifyingY = 1 + 4x

8 0

3 years ago

q(x)= x 2 −6x+9 x 2 −8x+15 q, left parenthesis, x, right parenthesis, equals, start fraction, x, squared, minus, 8, x, plus, 1

AURORKA [14]

According to the theory of rational functions, there are no vertical asymptotes at the rational function evaluated at x = 3.

<h3>What is the behavior of a functions close to one its vertical asymptotes?</h3>

Herein we know that the rational function is q(x) = (x² - 6 · x + 9) / (x² - 8 · x + 15), there are vertical asymptotes for values of x such that the denominator becomes zero. First, we factor both numerator and denominator of the equation to see evitable and non-evitable discontinuities:

q(x) = (x² - 6 · x + 9) / (x² - 8 · x + 15)

q(x) = [(x - 3)²] / [(x - 3) · (x - 5)]

q(x) = (x - 3) / (x - 5)

There are one evitable discontinuity and one non-evitable discontinuity. According to the theory of rational functions, there are no vertical asymptotes at the rational function evaluated at x = 3.

To learn more on rational functions: brainly.com/question/27914791

#SPJ1

8 0

2 years ago