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3 years ago

Find the slope of the graphed line

Mathematics

2 answers:

telo118 [61]3 years ago

6 0

The slope is 1 :) but the equation is y= 1x + 1

Alexxx [7]3 years ago

5 0

Answer:

Step-by-step explanation:

you do the rise over run, so count how many boxes up it is from one point to the next, then put that over how many boxes to the right it is, and simplify.

ex: 1/1 = 1, 2/2 = 1, 3/3 = 1, etc.

Hope this helps!

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Determine whether the graphs of the given equations are parallel, perpendicular, or neither.

12345 [234]

Answer:

A. Perpendicular

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2 years ago

Write the polynomial as a product: p^2q+r^2–pqr–pr<br> Thanks so much! Love you all who help!

Anarel [89]

Factor the equation so...
(r^2-pr) and (p^2q-pqr)

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Add a negative to r(r-p) to make it -r(p-r)

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3 years ago

Solve the triangle A = 2 B = 9 C =8

VARVARA [1.3K]

Answer:

$\begin{gathered} A=\text{ 12}\degree \\ B=\text{ 114}\degree \\ C=54\degree \end{gathered}$

Step-by-step explanation:

To calculate the angles of the given triangle, we can use the law of cosines:

$\begin{gathered} \cos (C)=\frac{a^2+b^2-c^2}{2ab} \\ \cos (A)=\frac{b^2+c^2-a^2}{2bc} \\ \cos (B)=\frac{c^2+a^2-b^2}{2ca} \end{gathered}$

Then, given the sides a=2, b=9, and c=8.

$\begin{gathered} \cos (A)=\frac{9^2+8^2-2^2}{2\cdot9\cdot8} \\ \cos (A)=\frac{141}{144} \\ A=\cos ^{-1}(\frac{141}{144}) \\ A=11.7 \\ \text{ Rounding to the nearest degree:} \\ A=12º \end{gathered}$

For B:

$\begin{gathered} \cos (B)=\frac{8^2+2^2-9^2}{2\cdot8\cdot2} \\ \cos (B)=\frac{13}{32} \\ B=\cos ^{-1}(\frac{13}{32}) \\ B=113.9\degree \\ \text{Rounding:} \\ B=114\degree \end{gathered}$ $\begin{gathered} \cos (C)=\frac{2^2+9^2-8^2}{2\cdot2\cdot9} \\ \cos (C)=\frac{21}{36} \\ C=\cos ^{-1}(\frac{21}{36}) \\ C=54.3 \\ \text{Rounding:} \\ C=\text{ 54}\degree \end{gathered}$

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1 year ago

Which angle is complimentary to 3?

MA_775_DIABLO [31]

Answer:

non of yhrm

Step-by-step explanation:

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3 years ago

Which of the following represents the value of y ? Round to the nearest tenth .

lesya [120]

The answer I think is b

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3 years ago