Answer:
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Step-by-step explanation:
We want to find two things-- the speed of the boat in still water and the speed of the current. Each of these things will be represented by a different variable:
B = speed of the boat in still water
C = speed of the current
Since we have two variables, we will need to find a system of two equations to solve.
How do we find the two equations we need?
Rate problems are based on the relationship Distance = (Rate)(Time).
Fill in the chart with your data (chart attached)
The resulting speed of the boat (traveling upstream) is B-C miles per hour. On the other hand, if the boat is traveling downstream, the current will be pushing the boat faster, and the boat's speed will increase by C miles per hour. The resulting speed of the boat (traveling downstream) is B+C miles per hour. Put this info in the second column in the chart. Now plug it into a formula! <u>Distance=(Rate)(Time) </u>Now solve using the systems of equations!
After every drop,the ball bounces to half it's previous height. With that understood.
1st drop -The ball drops 10m
1st bounce - 5m up
2nd drop - 5m down
2nd bounce - 2.5m up
3rd drop - 2.5m down
3rd bounce - 1.25m up
4th drop - 1.25m down
4th bounce - 0.625m up
5th/last drop - 0.625m down
To find the total vertical distance, you add them all.
10+5+5+2.5+2.5+1.25+1.25+0.625+0.625
=29.25m travelled in all.