Answer:
See pmf of Y below
Step-by-step explanation:
Let's abbreviate the days by using the first letter, W, T, F and S.
The following array shows the possible probabilities for Y.
Since the probabilities are independent Y(a,b) = P(a)*P(b) for any day a,b.
The array shows the pmf of Y, that is, the probability that the number of days <em>beyond TUESDAY</em> (as we are considering W) that it takes for both magazines to arrive after Wednesday equals to or is greater than 0.
![\bf \left[\begin{array}{ccccc}Day&W&T&F&S\\W&0.28^2&0.28*0.38&0.28*0.21&0.28*0.13\\T&0.38*0.28&0.38^2&0.38*0.21&0.38*0.13\\F&0.21*0.28&0.21*0.38&0.21^2&0.21*0.13\\S&0.13*0.28&0.13*0.38&0.13*0.21&0.13^2\end{array}\right]](https://tex.z-dn.net/?f=%5Cbf%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccc%7DDay%26W%26T%26F%26S%5C%5CW%260.28%5E2%260.28%2A0.38%260.28%2A0.21%260.28%2A0.13%5C%5CT%260.38%2A0.28%260.38%5E2%260.38%2A0.21%260.38%2A0.13%5C%5CF%260.21%2A0.28%260.21%2A0.38%260.21%5E2%260.21%2A0.13%5C%5CS%260.13%2A0.28%260.13%2A0.38%260.13%2A0.21%260.13%5E2%5Cend%7Barray%7D%5Cright%5D)
computing the probabilities, we get the array
![\bf \left[\begin{array}{ccccc}Day&W&T&F&S\\W&0.0784&0.1064&0.0588&0.0364\\T&0.1064&0.1444&0.0798&0.0494\\F&0.0588&0.0798&0.0441&0.0237\\S&0.0364&0.0494&0.0273&0.0169\end{array}\right]](https://tex.z-dn.net/?f=%5Cbf%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccc%7DDay%26W%26T%26F%26S%5C%5CW%260.0784%260.1064%260.0588%260.0364%5C%5CT%260.1064%260.1444%260.0798%260.0494%5C%5CF%260.0588%260.0798%260.0441%260.0237%5C%5CS%260.0364%260.0494%260.0273%260.0169%5Cend%7Barray%7D%5Cright%5D)
The right way to read Y is Y(row,column). For example, the probability that magazine 1 arrives on Thursday and magazine 2 arrives on Friday is Y(T,F) = 0.0798.
Answer:
6, 3
Step-by-step explanation:
Or 2 times 2 times 2 times 2 times 2 times 2 times 2
So, 2^6 is:
64
Now, 7^4 is:
2,401
Hope it helps!
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<h3>Answer = -7</h3>
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<h3>Known</h3>
a = 13
U2 = 6
U3 = -1
U4 = -8
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<h3>Question</h3>
d = ..?
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<h3>Way to do </h3>
#since it gives a lot of number, i will just pick one of the nth term, ill choose U2
Un = a + (n-1)d
U2 = 13 + (2-1)d
6 = 13 + d
6 - 13 = d
d = -7
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<h3>Note</h3>
• The formula of arithmetic sequence
<h2>Un = a + (n-1)d</h2>
n = nth term
a = first term
d = common difference
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Answer:
9
Step-by-step explanation:
.9*10=10
it's basically simple multiplication with a decimal
