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2 years ago

How to multiply a mixfraction by a whole number

2 answers:

8 0

To multiply a mixed fraction by a whole number here is an example:
Convert the mixed number into an improper fraction suppose we had
5 2/6 convert it into a improper fraction which is 32/6 then the the whole number that you are going to multiply it by suppose we had the number 3 you would then have to make 3 the whole number into a fraction 3/1 then you would multiply 32/6 by 3/1 and you would get 96/6 if it were simplified it would be 16/3
Hope i helped :))

natta225 [31]2 years ago

3 0

Convert to Improper Fractions.Multiply the Fractions.convert the result back to Mixed Fractions.

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2 years ago

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2 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

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Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

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2 years ago