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elena-14-01-66 [18.8K]
3 years ago
11

Please help me with this !

Mathematics
1 answer:
Bogdan [553]3 years ago
6 0

9514 1404 393

Answer:

  (a)  30%

Step-by-step explanation:

The number in the section marked "car" is 15.

The total of the numbers in all sections is (working CW) ...

  15 + 10 + 5 + 20 = 50

Then the fraction that come by car is ...

  car/total = ...

  15/50 = 30/100 = 30%

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Write the sum of 83 and<br> a numbers in a mathematical <br> atical way.
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83 + n

Step-by-step explanation:

The sum of 83 and a number would be 83 + n as an expression, where n is "said number".

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Please help asap xoxo
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It should be C

Step-by-step explanation:

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A city has<br> 12 parking spots on each block. How many parking spots are there on 6<br> Blocks
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How to do the equation x-5=17
Roman55 [17]

Answer:

X= 22

Step-by-step explanation:

x-5=17

To solve,

Since five is being subtracted from x, to get x by itself, add five to both sides

x-5=17

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3 years ago
Consider the quadratic equation x2 = 4x - 5. How many solutions does the equation have?
JulijaS [17]

Answer:

  • no real solutions
  • 2 complex solutions

Step-by-step explanation:

The equation can be rearranged to vertex form:

  x^2 -4x = -5 . . . . . . . . . subtract 4x

  x^2 -4x +4 = -5 +4 . . . . add 4

  (x -2)^2 = -1 . . . . . . . . . show the left side as a square

  x -2 = ±√-1 = ±i . . . . . . take the square root; the right side is imaginary

  x = 2 ± i . . . . . . . . . . . . . add 2. These are the complex solutions.

_____

<em>Comment on the question</em>

Every 2nd degree polynomial equation has two solutions. They may be real, complex, or (real and) identical. That is, there may be 0, 1, or 2 real solutions. This equation has 0 real solutions, because they are both complex.

3 0
3 years ago
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