Answer:
five types of pointing devices
Explanation:
Ponting devices
Pointing means point something and the pointing devices are the input /peripheral devices those are used to point the pointer on the screen. We do move cursor on the screen to open the files or any icon.
There are many types of pointing devices but these are quite common which are given below
- Computer mouse
- Finger on touch screen.
- Joystick.
- Leap Motion.
- Light pen (pen)
1.Mouse
Mouse is most common type of input device that is used for pointing the data on the screen. We press it with our hands and keep pointing the things.
There are three types of mouse
- optical mouse
- wireless mouse
- trackball mouse.
2. Finger on touch screen
In this type of movement the fingers are input devices those we use to see the movement of pointer on the screen and this is most common in this century.
3.Joystick.
Joystick is another input device to point the cursor but it is mostly used in games. Children can use it smartly so it is inculcated in games usually.
4. Leap Motion
The Leap Motion (LM) controller is a latest 3D sensing device for hand posture interaction with a computer. It is having the capability sense the location of the fingers of the hands, as well as the palm position.
5.Light Pen
this is another pointing device which is mostly used to highlight and select the data on the screen.
Note: All of these above pointing devices are most common used now a days. These devices are having new conventions day by day for the ease of user. This era is basically the era of IT ,so the use of computer must be so easy and conventional for the user so, the innovations and improvement in such devices is made side by side.
Answer:
5) 3 0 0
Explanation:
Given data
int [] val = { 3, 10, 44 };
The total number of parameters of given array are 3, so total length of array is also 3.
The indexing of array starts with '0', Therefore the indexes of array with length zero are: {0,1,2}
The value of array at index 0 is = 3
similarly
value at index 1 = 10
value at index 2 = 44
Here, Int i = 1 is storing the value '1' in integer variable i.
In addition to that, any value of index 'i' of an array is selected using array[i].
Therefore,
val[i] = i-1 is copying the value (i-1 = 1-1 = 0) to the index '1' of the array because i = 1.
So value at index 1 would be = val[1] = 0
The term i++ is incrementing the value of i, it makes i =2
val[i] = i-1 is copying the value (i-1 = 1-1 = 0) to the index '2' of the array because i = 2 now.
So value at index 2 would be = val[2] = 0
Hence, the output would be {3 0 0}. So 5th option is correct.
Answer:
The addition of binary numbers is done by adding the digits starting from the right side of the numbers, in the same way as we add two or more base 10 numbers. In binary addition, the place values are given as ones, twos, fours, eights, sixteens, etc.
Explanation:
OB: load test it because it will be telling you try again or error occurred
