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Alex787 [66]
3 years ago
14

Please help if you can :)

Mathematics
1 answer:
galben [10]3 years ago
7 0

Answer:

In the pictures linked.

Step-by-step explanation:

The pictures I linked have the answers. Brainly wouldn't let me submit it because I apparently used bad words.

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Someone help me please!
dalvyx [7]

Answer:

y = 4x + 8

Step-by-step explanation:

1) Find slope:

y2-y1/x2-x1

12-8/1-0 = 4/1 = 4

Slope = 4

2) Plug in a point in point-slope form

y-y1=m(x-x1)

y-8=4(x-0) =

y-8=4x-0 -> add 8 to both sides

y=4x+8

3 0
2 years ago
Find the equation of the graphed line.
GrogVix [38]

Answer:

  a.  y = -1/2x - 2

Step-by-step explanation:

The correct answer choice can be determined by finding the slope of the line. The slope is the ratio of rise to run.

__

<h3>slope</h3>

The x-intercept is 4 units left of the y-axis. As the line "runs" those 4 units, it "rises" -2 units to intercept the y-axis at -2. The slope of the line is ...

  m = rise/run = -2/4 = -1/2

In the slope-intercept form of the equation of a line, the slope is the coefficient of x. This information is sufficient to let us choose the first answer choice.

__

<h3>equation</h3>

The slope-intercept equation is ...

  y = mx +b . . . . . . . slope m, y-intercept b

We know the slope is -1/2, and the y-intercept is where x=0, at y=-2. Then the equation is ...

  y = -1/2x -2 . . . . . matches choice A

_____

<em>Additional comment</em>

When answering multiple-choice questions, you only need to do enough work to tell which answers are <em>not</em> viable.

When we plot the points, we see that the line has negative slope. (eliminates choice C). The slope is shallow, rather than steep (the x-intercept is farther from the origin than the y-intercept), so the magnitude of the slope is less than 1 and choices B and D are eliminated.

8 0
1 year ago
Here are two polygons on a grid. Is PQRST a scaled copy of ABCDE?
Bezzdna [24]

*see attachment showing the two polygons in a grid.

Answer:

No, PQRST is not a scale copy of ABCDE because we the sides are not increased proportionally.

Step-by-step explanation:

A polygon can be said to be a scaled copy of another polygon, if the the same scale factor is used in scaling every segment of the preimage or original image to get the length of the corresponding segments of the scale copy or image. In order words, all segments must be scaled proportionally.

Polygon PQRST, which is the new image, has different scale factors used in scaling the various segments of the preimage. In simple terms, the sides of PQRST were not increased proportionally. Therefore, PQRST is not a scaled copy of ABCDE.

5 0
3 years ago
1. Attiana bought 5 packets of pumpkin seeds. Each packet contained 32 seeds. Attiana planted 1 packet of the seeds and 20 seeds
Verdich [7]
Hehshsbshzujssvgsisksbegw
4 0
2 years ago
Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations
marusya05 [52]

Answer:

Sin \angle A =0.80

Cos \angle A=0.60

Sin \angle B =0.60

Cos \angle B=0.80

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

Sin \theta =\frac{Opposite}{Hypotenuse} and

Cos \theta =\frac{Adjacent}{Hypotenuse}

So:

Sin \angle A =\frac{BC}{BA}

Substitute values for BC and BA

Sin \angle A =\frac{8cm}{10cm}

Sin \angle A =\frac{8}{10}

Sin \angle A =0.80

Cos \angle A=\frac{AC}{BA}

Substitute values for AC and BA

Cos \angle A=\frac{6cm}{10cm}

Cos \angle A=\frac{6}{10}

Cos \angle A=0.60

Solving (b): Sine and Cosine B

In trigonometry:

Sin \theta =\frac{Opposite}{Hypotenuse} and

Cos \theta =\frac{Adjacent}{Hypotenuse}

So:

Sin \angle B =\frac{AC}{BA}

Substitute values for AC and BA

Sin \angle B =\frac{6cm}{10cm}

Sin \angle B =\frac{6}{10}

Sin \angle B =0.60

Cos \angle B=\frac{BC}{BA}

Substitute values for BC and BA

Cos \angle B=\frac{8cm}{10cm}

Cos \angle B=\frac{8}{10}

Cos \angle B=0.80

Using a calculator:

A = 53^{\circ}

So:

Sin(53^{\circ}) =0.7986

Sin(53^{\circ}) =0.80 -- approximated

Cos(53^{\circ}) = 0.6018

Cos(53^{\circ}) = 0.60 -- approximated

B = 37^{\circ}

So:

Sin(37^{\circ}) = 0.6018

Sin(37^{\circ}) = 0.60 --- approximated

Cos(37^{\circ}) = 0.7986

Cos(37^{\circ}) = 0.80 --- approximated

8 0
3 years ago
Read 2 more answers
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