1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sertanlavr [38]
3 years ago
5

Could anyone help please?

Mathematics
1 answer:
julsineya [31]3 years ago
7 0

Answer:

9.6 or round it to 10

Step-by-step explanation:

brainliest pls

You might be interested in
One more... and ill be out of yalls hair.
Zarrin [17]
Awnser:69
I had this question a few minutes ago, that’s funny
7 0
2 years ago
How do you fraction decimals and percents and all of that
Korvikt [17]
From fraction to decimal:  divide the numerator by the denominator 

From decimal to percent: move the decimal two places to the right. For example: 0.062=6.2%

From percent to decimal: move the decimal point two steps to the left. For example: 56%=0.56

From decimal to fraction: Rewrite the decimal number number as a fraction (example: <span>2.625=<span>2.6251</span></span>) an then Multiply by 1 to eliminate 3 decimal places, we multiply numerator and denominator by 10 cubed = 1000<span><span><span>2.625/1</span>×<span>1000/1000</span>=<span>2625/1000 and don forget to reduce if possible;)

</span></span></span>
3 0
3 years ago
On which interval is the average rate of change for bicycle production the greatest? A) 1950 to 1960 B) 1960 to 1970 C) 1970 to
Alborosie

Answer:

D) 1980 to 2000

Step-by-step explanation:

Finding the average rate of change in each interval to determine the greatest one.

Production per interval

1950-1960 = (21-11) \ million = 10 million

1960-1970 = (41-21)\ million = 20 million

1970-1980 = (71-41)\ million = 30 million

1980-2000 = (161-71)\ million= 90 million

Rate of change (1950-1960)= \frac{10}{11} \times 100= 90.90\%

Rate of change (1960-1970) = \frac{20}{21} \times 100= 95.23\%

Rate of change (1970-1980)=  \frac{30}{41} \times 100= 73.17\%

Rate of change (1980-2000)= \frac{90}{71} \times 100= 126.76\%

∴ rate of change between 1980 to 2000 is 126.78%

7 0
3 years ago
I need help with the steps. The answer is (5,2)
Elden [556K]

So with this, I will be using the substitution method. With the first equation, substitute (y+3) into the x variable and solve for y:

y+3+y=7\\2y+3=7\\2y=4\\y=2

Next, now that we have the value of y, substitute it into either equation to solve for x:

x+2=7\\x=5\\\\x=2+3\\x=5

<u>And this is how you get your final answer (5,2).</u>

5 0
3 years ago
Given that ABCD is a rhombus, what is the value of x?<br>(3x - 26)​
ExtremeBDS [4]
<h2>The required "option B) 20.75\°" is correct.</h2>

Step-by-step explanation:

You can refer figure:

brainly.com/question/4386376

To find, the value of x = ?

We know that,

Consecutive angles are supplementary

The diagonals bisect the angles.

2x\°+2(3x+7)\°=180\°

Divided by 2 both sides, we get

⇒ x\°+(3x+7)\°=90\°

⇒ x\°+3x+7\°=90\°

⇒ 4x=90\°-7\°

⇒ 4x = 83\°

⇒ x=\dfrac{83\°}{4}

⇒ x=20.75\°

∴ The value of x =20.75\°

Thus, the required "option B) 20.75\°" is correct.

7 0
3 years ago
Read 2 more answers
Other questions:
  • Rico tried to solve an equation step by step.
    8·2 answers
  • Find the interest is you invest $3500 for 9 years at a rate of 4.5%
    15·1 answer
  • Math help!!! Can somebody answer 1&amp;2.
    10·1 answer
  • 25 16 49 63 81 which one is different
    8·1 answer
  • Solve by the linear combination method. 2x + 3y = 11 –4x + 2y = 2 60pts please answer in 5 minutes
    6·1 answer
  • Consider the data set on the number line. Determine the mean absolute deviation. Round to the nearest tenth. A) 5.2 B) 6.3 C) 12
    15·1 answer
  • 2
    8·1 answer
  • 1. 4&lt;7 Multiply both sides by 7, then by 6, then by 3, then by 10
    7·1 answer
  • What is 9:21 equal to in rational form
    8·1 answer
  • Solve the equation (x over x+2) - (4 over x-2) = 1
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!