A single die is rolled. find the probability of rolling an odd number or a number less than 4.

The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took the customers in t

andreyandreev [35.5K]

Answer:

The test statistic is c. 2.00

The p-value is a. 0.0456

At the 5% level, you b. reject the null hypothesis

Step-by-step explanation:

We want to test to determine whether or not the mean waiting time of all customers is significantly different than 3 minutes.

This means that the mean and the alternate hypothesis are:

Null: $H_{0} = 3$

Alternate: $H_{a} = 3$

The test-statistic is given by:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

Sample of 100 customers.

This means that $n = 100$

3 tested at the null hypothesis

This means that $\mu = 3$

The average length of time it took the customers in the sample to check out was 3.1 minutes.

This means that $X = 3.1$

The population standard deviation is known at 0.5 minutes.

This means that $\sigma = 0.5$

Value of the test-statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{3.1 - 3}{\frac{0.5}{\sqrt{100}}}$

$z = 2$

The test statistic is z = 2.

The p-value is

Mean different than 3, so the pvalue is 2 multiplied by 1 subtracted by the pvalue of Z when z = 2.

z = 2 has a pvalue of 0.9772

2*(1 - 0.9772) = 2*0.0228 = 0.0456

At the 5% level

0.0456 < 0.05, which means that the null hypothesis is rejected.

7 0

3 years ago

Find the base and height

Nadusha1986 [10]

Answer:

not enough information I don't know what g=

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What equation is graphed in this figure?

Ksivusya [100]

to get the equation of any straight line, we simply need two points off of it, let's use those two points in the picture below.

$(\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{2}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{0}}}\implies \cfrac{3}{1}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_2=m(x-x_2) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_2}{5}=\stackrel{m}{3}(x-\stackrel{x_2}{1})$

keeping in mind that for the point-slope form, either point will do, in this case we used the second one, but the first one would have worked just the same.