a. Find the probability that an individual distance is
greater than 214.30 cm
We find for the value of z score using the formula:
z = (x – u) / s
z = (214.30 – 205) / 8.3
z = 1.12
Since we are looking for x > 214.30 cm, we use the
right tailed test to find for P at z = 1.12 from the tables:
P = 0.1314
b. Find the probability that the mean for 20 randomly
selected distances is greater than 202.80 cm
We find for the value of z score using the formula:
z = (x – u) / s
z = (202.80 – 205) / 8.3
z = -0.265
Since we are looking for x > 202.80 cm, we use the
right tailed test to find for P at z = -0.265 from the tables:
P = 0.6045
c. Why can the normal distribution be used in part (b),
even though the sample size does not exceed 30?
I believe this is because we are given the population
standard deviation sigma rather than the sample standard deviation. So we can
use the z test.
Let the price at which she sells the hi-fi set be x ~
The Money that she lose at the end of 2 years :
Loss percentage is equal to :
So, the money she end up getting after selling that hi-fi set is 2500, that is also the money She have at the end of the two years ~
Answer:
Arrange the following number in descendig otder
Answer:
B.2 1/41
Step-by-step explanation:
In a perfect square trinomial of the form ax+bx+c where a, b and c are constants, the value of (b/2)²=ac
In the provided equation the value of a=1, b=-3 c=?
Therefore, (-3/2)²=c since a-the coefficient of x²=1 and 1×c=c
c=2.25= 2 1/4
Thus the trinomial x² - 3x + 2 1/4 is a perfect square.
Ans is <span>y, because Triangle JHK is similar to triangle LMK</span>
