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mote1985 [20]
3 years ago
6

2x(9x^2+5y) polynomial operations

Mathematics
1 answer:
Annette [7]3 years ago
6 0
Mathpapa will give you the answer to this and explain the steps!
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PLEASE HELP! I WILL MARK BRAINLIEST IF TWO PEOPLE WILL ANSWER!
Mila [183]

Answer = 5.5

You just have to add all the numbers together to get the answer

5 0
3 years ago
Is 7500000 meters greater than 750 kilometers
monitta
A kilometer is 1000 meters.
1000 time 750 equals 750000
So the answer is yes, 7500000 is greater than 750000
5 0
4 years ago
Prove that: (secA-cosec A) (1+cot A +tan A) =( sec^2A/cosecA)-(Cosec^2A/secA)<br>​
Ksju [112]

Step-by-step explanation:

(\sec A - \csc A)(1 + \cot A + \tan A)

=(\sec A - \csc A)\left(1 + \dfrac{\cos A}{\sin A} + \dfrac{\sin A}{\cos A} \right)

=(\sec A - \csc A)\left(1 + \dfrac{\cos^2 A + \sin^2 A}{\sin A\cos A} \right)

=(\sec A - \csc A)\left(\dfrac{1 + \sin A \cos A}{\sin A \cos A} \right)

=\left(\dfrac{\frac{1}{\cos A} - \frac{1}{\sin A}+\sin A - \cos A}{\sin A\cos A}\right)

=\dfrac{\sin A - \sin A \cos^2A - \cos A + \cos A\sin^2A}{(\sin A\cos A)^2}

=\dfrac{\sin A(1 - \cos^2A) - \cos A (1 - \sin^2 A)}{(\sin A\cos A)^2}

=\dfrac{\sin^3A - \cos^3A}{\sin^2A\cos^2A}

=\dfrac{\sin A}{\cos^2A} - \dfrac{\cos A}{\sin^2A}

=\left(\dfrac{1}{\cos A}\right)\left(\dfrac{\sin A}{1}\right) - \left(\dfrac{1}{\sin^2A}\right) \left(\dfrac{\cos A}{1}\right)

=\sec^2A\csc A -  \csc^2A\sec A

5 0
3 years ago
Please help I will give u points
MaRussiya [10]
The answer to this problem is B
7 0
3 years ago
Which expression is equivalent to this
WINSTONCH [101]

Answer: B) 2^(5/12)

Explanation:

The cube root is the same as an exponent of 1/3

\sqrt[3]{x} = x^{1/3}

Multiply this exponent 1/3 by the other exponents 5 and 1/4 to get

(1/3)*5*(1/4) = (1/3)*(5/1)*(1/4) = (1*5*1)/(3*1*4) = 5/12

which is the final exponent. The base 2 stays the same the entire time.

8 0
3 years ago
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