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2 years ago

2x(9x^2+5y) polynomial operations

Mathematics

1 answer:

Annette [7]2 years ago

6 0

Mathpapa will give you the answer to this and explain the steps!

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In a group of 120 farmers, 65 grow maize and 75 grow cassava. Of these 35 grow both maize and cassava.

Simora [160]

30 farmers grow it I think.

5 0

3 years ago

Trigonometry: <br>1) Work out the bearing from B to C. <br>2) Calculate the bearing of D from B

kakasveta [241]

Answer:

see below

Step-by-step explanation:

a bearing is the angle in degrees measured clockwise from north.

Triangle ABC is a right triangle

Tan C = opp side / hyp

tan C = AB / CA

tan C = 30/30

tan C = 1

taking the inverse tan

tan ^ -1 tan C = tan ^ -1 ( 1)

C = 45 degrees

This is 90+45 degrees from North

135 degrees from north

Tan B = opp side / hyp

tan B = AD/BA

tan B = 45/30

tan B = 3/2

taking the inverse tan

tan ^ -1 tan B = tan ^ -1 ( 3/2)

D = 56.30993247

Add 180 degrees

180+56.30993247

236.3099325 from north

7 0

3 years ago

What is the missing value?

lorasvet [3.4K]

Answer:

The missing value is 19.

Step-by-step explanation:

The equation is increasing by 2 and 17+2 equals 19.

4 0

2 years ago

Find the distance between the pair of points (18, -18) and (-17, -25)

MakcuM [25]

Answer:

35.6931366

Step-by-step explanation:

distance = to square root of (x2-x1)^2+(y2-y1)^2

substiute in the equation

so square root of (-17-18)^2+(-25--18)^2

=7square root of 26

or 35.6931366

3 0

2 years ago

The population of Henderson City was 3,381,000 in 1994, and is growing at an annual rate 1.8%

liq [111]

<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>

Step-by-step explanation:

Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.

From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by $\frac{100+1.8}{100}$ = $\frac{101.8}{100}$ .

So, the population in the year t can be given by $P(t)=3,381,000\textrm{x}(\frac{101.8}{100})^{(t-1994)}$

Population in the year 2000 = $3,381,000\textrm{x}(\frac{101.8}{100})^{6}$ = $3,762,979.38$

Population in year 2000 = 3,762,979

Let us assume population doubles by year $y$ .

$2\textrm{x}(3,381,000)=(3,381,000)\textrm{x}(\frac{101.8}{100})^{(y-1994)}$

$log_{10}2=(y-1994)log_{10}(\frac{101.8}{100})$

$y-1994=\frac{log_{10}2}{log_{10}1.018}=38.8537$

$y$ ≈ $2033$

∴ By 2033, the population doubles.

4 0

3 years ago