So, you want 4 of each kind.
Pick any set of 4 from each kind, and then there will be 12! ways to play them.
21C4 * 13C4 * 25C4 * 12! = 2.593*10^19
Answer:
A gestation length of 279 days represents the 18th percentile.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In a certain breed of cattle, the length of gestation has a mean of 284 days and a standard deviation is 5.5 days.
This means that 
What length of gestation, rounded to the nearest whole number, represents the 18th percentile?
This is X when Z has a pvalue of 0.18. So X when Z = -0.915.




A gestation length of 279 days represents the 18th percentile.
Answer:
The second option
Step-by-step explanation:
1/3x represents the one-third of a number and quotient indicates division. That's the only option with both 1/3x and a division sign