A. Determine the possible amount of money gail could have
6.70, 6.700, 6.7000, 6.70000, and so on.
Answer:
30%
Step-by-step explanation:
Total number of people registered for the two days seminar = 1000
90% of those registered attended on the first day
This means (90/100)1000 = 900 people attended the seminar on the first day.
That means 100(1000 -900) registered people did not attend the seminar on the first day
80% of those registered attended on the second day
This means (80/100)1000 = 800 people attended the seminar on the second day.
That means 200 (1000 -800) registered people did not attend the seminar on the second day
The percent of those registered did not attend the seminar on either day = 100 + 200 = 300
= 30%
Total = Group A + Group B - (both + neither)
1000 = 900 + 800 - (B + N)
The two unknown variables (both and neither)
Answer: 10
Step-by-step explanation:
use a^2 + b^2 = c^2
where a = |y2 - y1| = 11 - 3 = 8
where b = |x2 - x1| = |-2 - 4| = |-6| = 6
8^2 + 6^2 = c^2
100^2 = c^2
c = 10
You want to find
P(1000 < X < 3000)
where X is normally distributed with mean 1751 and standard deviation 421. Transform X to Z, so that it follows the standard normal distribution with mean 0 and standard deviation 1 using the relation
X = 1751 + 421Z ==> Z = (X - 1751)/421
Then
P(1000 < X < 3000) = P((1000 - 1751)/421 < (X - 1751)/421 < (3000 - 1751)/421)
… ≈ P(-1.783 < Z < 2.967)
… ≈ P(Z < 2.967) - P(Z < -1.783)
… ≈ 0.9985 - 0.0373
… ≈ 0.9612
so that approximately 96.1% of the students fall in this income range.