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3 years ago

6 stools and 4chairs cost$58 but 5 stools and 2 chairs cost$ 35 find the cost of each stool and each chair

1 answer:

6 0

Stool = s, chair = c
6s+4c=58 ---(1)
5s+2c=35 ---(2)

(2)*2; 10s+4c=70 ---(3)
(3)-(1); 4s=12
so s=3
from (2)
5s+2c= 35
5(3)+2c=35
2c = 35-15
2c = 20
so c=10

then the cost of each stool is $3 and the cost of each chair is $10

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4 years ago

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The net change in how many bags are on the shelf, from the beginning of Tuesday to the end of Monday is -2.

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The change in the number of bags any day is the number of bags is equal to the number of bags purchased to restock less the number of bags sold that day.

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At the end of Tuesday, the change is:

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At the end of Wednesday, the change is:

Restock: 12

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Change: 12 - 8 = 4 (the number of bags increases by 4)

At the end of Thursday, the change is:

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Change: 12 - 2 = 10 (the number of bags increases by 10)

At the end of Friday, the change is:

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Sales: 19

Change: 18 - 19 = - 1 (the number of bags decreases by 1).

At the end of Saturday, the change is:

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Sales: 22

Change: 24 - 22 = 2 (the number of bags increases by 2).

At the end of Sunday, the change is:

Restock: 0

Sales: 15

Change: 0 - 15 = - 15 (the number of bags decreases by 15).

At the end of Monday, the change is:

Restock: 0

Sales: 3

Change: 0 - 3 = - 3 (the number of bags decreases by 3).

The net change in how many bags are on the shelf, from the beginning of Tuesday to the end of Monday equals the algebraic sum of every change:

Net change = 1 + 4 + 10 + (-1) + 2 + (-15) + (-3)

Using associative property: (1 + 4 + 10 + 2) - (1 + 15 +3)

Simplifying: 17 - 19 = -2

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3 years ago

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