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lana66690 [7]
3 years ago
8

The relative growth rate for a certain type of fungi is 70% per hour. A small culture has formed and in just 6 hours the count s

hows to be 54,273 fungi in the culture. What is the initial number of fungi in the culture?
Mathematics
1 answer:
Maru [420]3 years ago
8 0

We are given with

relative growth rate = 70%

time = 6 hours

count after 6 hours = 54273


And we are asked to fine the initial number of fungi. We use the equation:

54273 = Ao (1.7)^6

Solving for Ao

Ao = 2248


The initial number of fungi is 2248.

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Julia is allowed to watch no more than 5 hours of television a week. So far this week, she has watched 1.5 hours. Write and solv
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Answer:

The inequality to show how many hours of television Julia can still watch this week can be given as:

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x\leq3.5

Thus, Julia can still watch no more than 3.5 hours of television this week.

Step-by-step explanation:

Given:

Julia is allowed to watch television no more than 5 hours a week.

She has already watched 1.5 hours

To write and solve an inequality to show how many hours of television Julia can still watch this week.

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Let the number of hours of television that Julia can still watch this week be = x

Number of hours already watched = 1.5

Total number of hours of watching television this week would be given as:

⇒ x+1.5

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Thus, the inequality can be given as:

⇒ x+1.5\leq 5

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Subtracting both sides by 1.5

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6 0
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As per the problem, the given triangle is a right triangle. This is signified by the box around one of its angles, this box states that the angle it is surrounding is a right angle.

Since it is a right triangle, one can use the Pythagorean theorem to solve this problem. The Pythagorean theorem states that; (a^2 + b^2 = c^2), where (a) and (b) are the legs of the right triangle, or the sides adjacent to the right angle. (c) is the hypotenuse or the side opposite the right angle.

Substitute in the given values and solve, note that (a) represents the unknown leg (side).

a^2 + b^2 = c^2\\\\a^2 + (\sqrt{19})^2 = (100)^2\\\\a^2 + 19 = 100

Inverse operations,

a^2 + 19 = 100\\-19\\\\a^2 = 81\\\\a = \sqrt{81}\\\\a = 9

8 0
2 years ago
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