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MrRissso [65]
3 years ago
11

Please hurry; Toni's grandparents bought a house in 1975 for $28, 000. Every decade, the value of the house doubles. What will b

e the house's value be in 2020, to the nearest thousand?
a $317, 000
b $448, 000
c $634, 000
d $896, 000
Mathematics
2 answers:
OleMash [197]3 years ago
8 0

Answer:

b

Step-by-step explanation:

His initial cost is $28,000. Every decade the value of the house doubles. We are in year 1975. Let's add 10 years (a decade) 1975+10= 1985. Since we added ten years, we will double $28,000 which is $56,000. Let's add 10 more years 1985+10 is 1995. Since we added 10 years more, we double $56,000 which is $112,000. Now we can still add 10 more years. Do the same thing you did for the first and second decades. You should get the year 2005 and $224,000. We can still add 10 more years to get to 2020. Our year will be 2015 and our total amount in dollar is $224,000² = $448,000. Since the value doubles every decade you ignore the 5.

lyudmila [28]3 years ago
6 0

Answer:

c. $634,000

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

\text{If}\ a,\ b,\ c,\ d,\ e,\ ...\ \text{is a geometric sequence, then}\ \dfrac{b}{a}=\dfrac{c}{b}=\dfrac{d}{c}=\dfrac{e}{d}=....\\\\\#1\\\\\dfrac{7.5}{10}=0.75\\\dfrac{5.625}{7.5}=0.75\\\dfrac{4.21875}{5.625}=0.75\\\boxed{YES}\\================================\\

\#2\\\\\dfrac{40}{160}=\dfrac{1}{4}\\\dfrac{10}{40}=\dfrac{1}{4}\\\dfrac{2.5}{10}=\dfrac{1}{4}\\\boxed{YES}\\================================\\

\#3\\\\\dfrac{70}{20}=3.5\\\dfrac{245}{70}=3.5\\\dfrac{857.5}{245}=3.5\\\boxed{YES}\\================================\\

\#4\\\\\dfrac{16.5}{13}=\dfrac{165}{130}=\dfrac{33}{26}\\\dfrac{20}{16.5}=\dfrac{200}{165}=\dfrac{40}{33}\neq\dfrac{33}{26}\\\boxed{NO}\\================================\\

\#5\\\\\dfrac{5.5}{5}=1.1\\\dfrac{6.05}{5.5}=1.1\\\dfrac{6.655}{6.05}=1.1\\\boxed{YES}\\================================\\

\#6\\\\\dfrac{17.1}{16}=1.06875\\\dfrac{18.2}{17.1}=1.0643274..\neq1.06875\\\boxed{NO}

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