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2 years ago

7

Can y’all help me Solve for q

1 answer:

Anettt [7]2 years ago

4 0

Sorry I needed the points

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Find the measure of the missing angles.

Vlada [557]

Answer:

y=145 and x=55

Step-by-step explanation:

Subtract 180 by 35 for y and 90-35 for x. Hope this helps again. Lol

5 0

1 year ago

Write a word problem involving fractions for which you would use the work backward strategy and addition to solve. Include solut

Delicious77 [7]

Mrs. Annie went to a store, spent half of her money and then $10 more. She went to a second store, spent half of her remaining money and then $10 more. But she then had no money left. How much money did she have to begin with when she went to the first store?
Answer: $60

7 0

2 years ago

The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

5 0

2 years ago

Find the value of the variable.

nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC; ${}$ in triangle ΔFGH;

Segment $\overline {AB}$ = 14 ${}$ Segment $\overline {FG}$ = 14

Segment $\overline {BC}$ = 27 ${}$ Segment $\overline {GH}$ = 19

Segment $\overline {AC}$ = 19 ${}$ Segment $\overline {FH}$ = 2·y + 5

∡A = 32° ${}$ ∡G = 32°

∡A = ∠BAC which is the angle formed by segments $\overline {AB}$ = 14 and $\overline {AC}$ = 19

Therefore, segment $\overline {BC}$ = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments $\overline {FG}$ = 14 and $\overline {GH}$ = 19

Therefore, segment $\overline {FH}$ = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

$\overline {FH}$ ≅ $\overline {BC}$ by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ $\overline {FH}$ = $\overline {BC}$ = 27° y definition of congruency

$\overline {FH}$ = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

8 0

2 years ago

The sum of a students three scores is 217. If the first is 30 points more than the the second, and the sum of the first two is 1

nekit [7.7K]

Answer:

First score is 90

Step-by-step explanation:

Let A represent the first score

Let B represent the second score

Let C represent the third score

A+B+C=217 equation 1

If the first score A is 30 points more than the second,B

A=B-30 equation 2

Lastly,sum of A&B is 16 more than 2C

A+B=2C+16 equation 3

From equation 1

A+B=217-C equation 4

substitute for A+B in equation 3

217-C=2C+16

217-16=2C+C

201=3C

C=67

substituting C in equation 4

A+B=217-67

A+B=150

if the first score more than the first,then the first 90 while second 60 since A+B=150

3 0

2 years ago

Read 2 more answers