Complete the equation for the relationship between the weight and number of months

Mathematics

1 answer:

Alisiya [41]2 years ago

5 0

Y=5.5x because it just is

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What is 3x-2y=24 in slope intercept form??

elixir [45]

Answer: 3x-2y=24 in slope intercept form is $y=\frac{2}{3}x -12$

The graph of the equation is in the attachment

Step-by-step explanation: Slope intercept form is y = mx + b

m is the slope b is the y-intercept x is the "input" in the equation y is the "output" or the y-value in the graph for a given x-value.

You need to rearrange the standard form to slope-intercept to isolate y on the left side of the equation.

3x - 2y = 24 Standard form. Subtract 3x from both sides.

-2y = -3x + 24 divide both sides by -2

-2y/-2 = -3x/-2 + 24/-2 . Simplify.

y = 3x/2 - 12 .

To clarify the slope as a fraction

$y=\frac{2}{3}x -12$

4 0

2 years ago

how much would $150 invested at 8% interest compounded anually be worth after 13 years? A(t)=P(1+r/n)^

PIT_PIT [208]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$150\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &13
\end{cases}
\\\\\\
A=150\left(1+\frac{0.08}{1}\right)^{1\cdot 13}\implies A=150(1.08)^{13}\implies A\approx 407.9435589$