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pashok25 [27]
4 years ago
8

Which statement is true about the box plots? A number line goes from 0 to 13. Marc's class's whiskers range from 1 to 10, and th

e box ranges from 3 to 9. A line divides the box at 5. Sue's class's whiskers range from 3 to 12, and the box ranges from 5 to 10. A line divides the box at 9. Both the ranges and the interquartile ranges for the data sets are the same. Neither the ranges nor the interquartile ranges for the data sets are the same. The interquartile ranges for the box plots are the same, but their ranges are different. The ranges for the box plots are the same, but their interquartile ranges are different.
Mathematics
2 answers:
kondor19780726 [428]4 years ago
8 0

Answer:

The answer is D.

Step-by-step explanation:

Subtract the minimum from the maximum in both data sets, and you get the range: For both, it is nine.

Therefore, the ranges for the box plots are the same, but their interquartile ranges are different.

Arada [10]4 years ago
6 0

Answer:

The Answer On Edge Is D.), Have Fun Dreamers!

Step-by-step explanation:

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Use the distance formula to determine the distance between (-8,10) and (-6,7)
hjlf

Answer:

Distance: \sqrt{13} units

Step-by-step explanation:

The distance formula is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where:

  • d is the distance between points (x_1,y_1) and (x_2,y_2)
  • (x_1,y_1) are the coordinates of the first point
  • (x_2,y_2) are the coordinates of the second point

We are given that:

  • (x_1,y_1)=(-8,10)
  • (x_2,y_2)=(-6,7)

To determine the value of our distance, d, we plug in our given information into the formula and solve for

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

d=\sqrt{(-6-(-8))^2+(7-10)^2}

d=\sqrt{(-6+8)^2+(-3)^2}

d=\sqrt{(2)^2+(-3)^2}

d=\sqrt{4+9}

d=\sqrt{13}

Therefore, the distance between (-8,10) and (-6,7) is \sqrt{13} units.

See the attached graph for a visual.

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3 years ago
Please help!!! If you're correct I'll mark.
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2x + y = 1 . . . (1)
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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