The maximum value can be determined by taking the derivative of the function.
(dh/dt) [h(t)] = h'(x) = -9.8t + 6
Set h'(x) = 0 to find the critical point
-9.8t + 6 = 0
-9.8t = -6
t = 6/9.8
Plug the time back into the function to find the height.
h(6/9.8) = -4.9(6/9.8)^2 + 6(6/9.8) + .6
= 2.4
And I don't understand your second question.
To solve this equation you need to first start by writing out the f(x)-g(X).
The equation should be 2x^2-4x-5+2x.
You then want to simplify the equation, I got 2x^2-2x-5.
You then want to plug in the x=5 for all the x's in the equation.
2(5)^2-2(5)-5 would be the equation.
The answer you get should be 35.
Answer:
i dont know cause you didnt give any of the answers that are in the boxes it would be helpful if you did that
Step-by-step explanation:
Answer: 45.24
Step-by-step explanation:
