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Elza [17]
3 years ago
9

PLEASE HELP!!!! WILL GIVE 15 POINTS

Mathematics
2 answers:
UNO [17]3 years ago
7 0

Answer:

11

Step-by-step explanation:

y = rx

22 = 2r

22/2 = r

11 = r

elena-s [515]3 years ago
6 0

Answer:

r=11x

Step-by-step explanation:

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Please help me w this
scoundrel [369]

Answer:

54

Step-by-step explanation:

54

8 0
3 years ago
Determine whether the geometric series is convergent or divergent. 10 − 6 + 3.6 − 2.16 + convergent divergent Correct: Your answ
Misha Larkins [42]

Answer:

The series CONVERGES with the sum being 6.25.

Step-by-step explanation:

Given that the geometric series is 10 - 6 + 3.6 - 2.16 + ....

So the first term of the geometric progression is, a_{1} = 10

The second term of the geometric progression is a_2 = -6 = a_1 × r = 10 × r

where r is the constant ratio.

Therefore r  = \frac{-6}{10} = -0.6

The third term of the geometric progression, a_3 = 3.6 = a_2 × r = -6 × -0.6 = 3.6

The fourth term of the geometric progression, a_4 = -2.16 = a_3 × r = 3.6 × -0.6 = -2.16

So the above confirms that the series is indeed a geometric progression with first term, a_{1} = 10 and constant ratio, r  = -0.6

Now to find if the series converges or diverges we can take sum of the series from first term to infinity.

We can already infer that the series is convergent since the constant ratio, r  = -0.6 which is less than 1.

So from the formula for the sum to infinity of a geometric progression, S, we get

S = \frac{a_1}{1 - r}  = \frac{10}{1 - (-0.6)} = \frac{10}{1 + 0.6}  = \frac{10}{1.6}  = 6.25

So the series is convergent with the sum being 6.25

7 0
4 years ago
What is the scientific notation of (1×10to the 3 power)
ale4655 [162]
That is easy its 1000
6 0
3 years ago
Can someone plz answer my last question
Luda [366]
What was it?
math?
health?

7 0
3 years ago
Read 2 more answers
Hi! Can you please help me? I am learning about like terms, and other things. I am kind of confused. Here is an example of what
tigry1 [53]

Your answer is 4z+10

Hope this helps

8 0
3 years ago
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