Open to find question (mathematics)

A car covered a certain distance at a speed of 24 mph. While returning, the car covered the same distance at a speed of 16 mph.

igomit [66]

Since the distances were the same you can find the average speed directly by adding the speeds then dividing by 2. No need to weight anything.

If we’re considering speed regardless of direction, the average speed is:

(24 + 16) / 2 = 40 / 2 = 20mph

However if direction matters, then one number has to be negative since the directions are opposite:

(24 - 16) / 2 = 8 / 2 = 4mph (in the positive direction)

Depending on the context, either of these could be your answer.

7 0

3 years ago

Read 2 more answers

I NEED TO TURN THIS IN BEFORE 8:15 PLEASE HELPPP

Iteru [2.4K]

Answer:

4

Step-by-step explanation:

5 0

3 years ago

Please help me! Due soon!

givi [52]

Answer:

70/9

Step-by-step explanation:

We have the quadratic:

$3x^2+4x-9$

So, let’s find the roots of the quadratic. We will set the expression equal to 0:

$3x^2+4x-9=0$

Testing for factors, we can see that our quadratic isn’t factorable.

So, we can use the Quadratic Formula. The quadratic formula is given by:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case:

$a=3, b=4,\text{ and } c=-9$

Therefore, by substitution:

$\displaystyle x=\frac{-(4)\pm\sqrt{(4)^2-4(3)(-9)}}{2(3)}$

Evaluate:

$\displaystyle x=\frac{-4\pm\sqrt{124}}{6}$

Simplify the square root:

$\sqrt{124}=\sqrt{4\cdot31}=2\sqrt{31}$

Hence:

$\displaystyle x=\frac{-4\pm2\sqrt{31}}{6}$

Reduce:

$\displaystyle x=\frac{-2\pm\sqrt{31}}{3}$

So, our roots are:

$\displaystyle x_1=\frac{-2+\sqrt{31}}{3}, x_2=\frac{-2-\sqrt{31}}{3}$

We want to find the sum of the <em>squares</em> of our two roots. So, let’s square each term:

$\displaystyle (x_1)^2=\Big(\frac{-2+\sqrt{31}}{3}\Big)^2$

Square. For the numerator, we can use the perfect square trinomial patten where:

$(a+b)^2=(a^2+2ab+b^2)$

Therefore:

$\displaystyle (x_1)^2=\Big(\frac{(-2)^2+2(-2)(\sqrt{31})+(\sqrt{31})^2}{9}\Big)$

Simplify:

$\displaystyle (x_1)^2=\frac{35-4\sqrt{31}}{9}$

Similarly, for the second root, we will have:

$\displaystyle (x_2)^2=\Big(\frac{-2-\sqrt{31}}{3}\Big)^2$

So:

$\displaystyle (x_2)^2=\Big(\frac{(-2)^2+2(-2)(-\sqrt{31})+(-\sqrt{31})^2}{9}\Big)$

Simplify:

$\displaystyle (x_2)^2=\frac{35+4\sqrt{31}}{9}$

Therefore, our sum will be:

$\displaystyle (x_1)^2+(x_2)^2\\\\ \begin{aligned} &=\frac{35-4\sqrt{31}}{9}+\frac{35+4\sqrt{31}}{9}\\&=\frac{35-4\sqrt{31}+35+4\sqrt{31}}{9}\\&=\frac{70}{9}\end{aligned}$

Therefore, our final answer is 70/9.

3 0

3 years ago

A baseball team played three consecutive home games. The first game was attended by 28,453 people. The second game was attended

Anna35 [415]

Answer:

add the amount for each day and multiply by 3

Step-by-step explanation:

28453+30678+24234/3

3 0

4 years ago

Find the area of a circle with a circumference of \blueD{12.56}12.56start color #11accd, 12, point, 56, end color #11accd units.

mote1985 [20]

Answer:

12.55

Step-by-step explanation:

A = C²/4pi (3.14....) = 12.56² ÷ 4 × pi (3.14...) ≈ 12.556363, in this case we only take 12.55

6 0

3 years ago