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Art [367]
3 years ago
11

What value of x will make ONM similar SRQ by the SAS similarity theorem?

Mathematics
2 answers:
Marta_Voda [28]3 years ago
7 0

Answer:

The correct answer is 25

Step-by-step explanation:

See the attached figure.

SAS similarity theorem mean that when two triangles have corresponding angles are congruent and corresponding sides with identical ratios the triangles are similar.

So, if ΔONM similar ΔSRQ by the SAS similarity theorem

∴∠N = ∠R

And

\frac{NM}{RQ} =\frac{NO}{RS}

given that NM = 10 , NO = 8 , QR = x , RS = 20

∴\frac{10}{x} =\frac{8}{20}

∴x=\frac{10*20}{8} =25

So, the value of x will make ONM similar SRQ by the SAS similarity theorem = 25

weqwewe [10]3 years ago
3 0

Answer:

Answer is B (25) I just took the test on Edg.

Step-by-step explanation:

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Okay. So I find it easiest to calculate the full area as if the shape was a rectangle, then subtracting open space. We already know that length is 100, so now we just need to find width. 50 + 25 + 50 + 25 + 50 = 200. 200 x 100 =20,000. So now we just need to find the areas of open space and subtract. Both spaces have a length of 75 and a width of 25. 25 x 75 = 1875. There were 2 spaces, and 1875 x 2 = 3,750. 20,000 - 3,750 = 16,250.


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3 years ago
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[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation
irina1246 [14]

Answer:

y=-\frac{158}{579}

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]

And the vector B is formed with the solution of each equation of the system:b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called A_{2}.

A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]

The value of y using Cramer's rule is:

y=\frac{det(A_{2}) }{det(A)}

Find the value of the determinant of each matrix, and divide:

y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}

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3 years ago
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Answer:

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Step-by-step explanation:

The area of a circle is found by

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Answer:

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