All categories

3 years ago

What is the slope of the line?

Mathematics

1 answer:

vivado [14]3 years ago

3 0

Do rise over run and you should end up with 4 and 3 hope that help

You might be interested in

The histogram shows how many pairs of sneakers are on sale at the local shoe store. How

snow_lady [41]

Answer: 22

Step-by-step explanation:

3 0

3 years ago

Please answer correctly !!!!!! Will mark brainliest !!!!!!!!!!!!!

romanna [79]

Answer:

x = - 9, x = 10

Step-by-step explanation:

Given

x² - x - 90 = 0

Consider the factors of the constant term (- 90) which sum to give the coefficient of the x- term (- 1)

The factors are - 10 and + 9, since

- 10 × 9 = - 90 and - 10 + 9 = - 1 , thus

(x - 10)(x + 9) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 10 = 0 ⇒ x = 10

x + 9 = 0 ⇒ x = - 9

lesser x = - 9

greater x = 10

5 0

2 years ago

I need help fast please!!

kaheart [24]

Solution set is: ( $7,\frac{13}{3}$ )

Option B is correct

Step-by-step explanation:

We need to find the solution to system of equations

$y=\frac{1}{3}x+2\\y=\frac{4}{3}x-5$

Let:

$y=\frac{1}{3}x+2\,\,\,eq(1)\\y=\frac{4}{3}x-5\,\,\,eq(2)$

Putting value of y from eq(2) into eq(1)

$\frac{4}{3}x-5=\frac{1}{3}x+2\\Combining\,\,like\,\,terms:\\\frac{4}{3}x-\frac{1}{3}x=2+5\\Taking\,\,LCM\\\frac{4x-1x}{3}=7\\\frac{3x}{3}=7\\x=7$

So, value of x=7

Putting value of x into equation 1 to find the value of y:

$y=\frac{1}{3}x+2\\y=\frac{1}{3}(7)+2\\y=\frac{7}{3}+2\\Taking\,\,LCM\\y=\frac{7+2*3}{3}\\y=\frac{7+6}{3}\\y=\frac{13}{3}$

So, value of y = $\frac{13}{3}$

Solution set is: ( $7,\frac{13}{3}$ )

Option B is correct

Keywords: System of equations

Learn more about system of equations at:

#learnwithBrainly

3 0

3 years ago

What would be a equation for (5,2) and (0,7)?

Genrish500 [490]

$\bf (\stackrel{x_1}{5}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{7}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{7}-\stackrel{y1}{2}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{5}}}\implies \cfrac{5}{-5}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{-1}(x-\stackrel{x_1}{5}) \\\\\\ y-2=-x+5\implies y = -x+7$

6 0

3 years ago

Is the bisector of ∠ABC and is the bisector of ∠ACB.

ycow [4]

Answer:

ASA

Step-by-step explanation:

You can show the angles at either end of segment BC in triangles MBC and LCB are congruent, so you have two angles and the segment between. The appropriate theorem in such a case is ASA.

7 0

3 years ago