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MrRissso [65]
3 years ago
6

The graph shows how many miles Barrett traveled over a 5 hour time frame. The point (1,50) is on the graph what is the unit rate

for the first hour?​
Mathematics
1 answer:
grandymaker [24]3 years ago
3 0

Answer:

Step-by-step explanation:

The answer is B 50

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It cost Naomi $7.70 to send 154 text messages. How many text messages did she send
s2008m [1.1K]

You have to find the unit rate

SO..

7.70 / 154 = 0.05

So it cost her 0.05 cents for each text.

So then you divide $ 5.25 by the unit rate to get the number of text

5.25 /0.05 = 105

so she sent 105 text

To check it you just multiply the unit rate by the number of text you got and you show come up with $ 5.25

0.05 x 105 = 5.25

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3 years ago
Matters has 456:8 What s his rate
Olegator [25]

We are given ratio 456:8.

The given ratio can be written in fraction form as \frac{456}{8}

In order to find the rate, we need to divide 456 by 8, because it would give the unit value.

When we divide 456 by 8, we first take multiple of 8 closer to the number 45.

8*6=48 but it's greater than 45, so we would take 8*5 =40.

Subtracting 40 from 45, we get 5.

Getting 6 down, we get 56. Take multiple of 8 upto 56.

8*7= 56.

56 -56=0.

So, on dividing 456 by 8 we got 57.

Therefore, rate is 57 per unit.


3 0
3 years ago
ms smith paid 125 to have her hair colored and cut. If she tips her hairdresser 15% of her bill, how much was the tip
elena-s [515]
The tip was $125 * 0.15, or $18.75.
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A. 33ft <br>B. 85 ft<br>C. 42ft<br>D. 14 ft
sleet_krkn [62]
B. The telephone pole is 85 ft tall.
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An air traffic controller spots two airplanes at the same altitude converging to a point as they fly at right angles to each oth
dedylja [7]

Answer:

(a) D(t) = 250t -500 miles

(b) Controller has 2 hours, but including time for pilots to divert course or altitude.

Step-by-step explanation:

Given:

two planes at same altitude heading in a collision course.

Plane A at 400 miles from collision point at 200 mph

Plane B at 300 miles from collision point at 150 mph.

Theoretical collision happens in

t = 400/200 = 300/150 = 2 hours

Distance ya of plane A from collision point as a function of time in hours

ya(t) = 400 -200t

Distance yb of plane B from collision point as a function of time in hours

yb(t) = 300-150t

(a) Distance between two planes,

Since the two planes are on courses perpendicular to each other, will need using pythagorean theorem

D(t) = sqrt(ya(t)^2+yb(t)^2)

= sqrt((400-200t)^2+(300-150t)^2)

= 250(t-2)

D(t) = 250t -500 miles

b. time available

Time until D(t) = 0

solve D(t) = 0

D(t) = 0

250(t-2) = 0

t = 2  (two hours)

3 0
3 years ago
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