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galben [10]
3 years ago
11

18 is greater than or equal to negative 2X.

Mathematics
1 answer:
garri49 [273]3 years ago
8 0

I assume you mean 18>=-2x?

1) 18>=-2x

2) -9>=x

3) -9<=x (keep note you have to do this when dividing or multiplying by a negative)

So the answer is -9 is less than or equal to x

Hope this helped!

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Write a translation rule that maps point D(7, -3) onto point D'(2, 5)
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Answer:

Step-by-step explanation:

We are given D (7, -3) and D'(2, 5).

the transformation

D'(x,y) → D(x-5, y+8).

Then  

x=7 → x=7-5 = 2

y=-3 → y=-3+8 = 5

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2 years ago
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3 years ago
I need help proving this ASAP
Ket [755]

Answer:

See explanation

Step-by-step explanation:

We want to show that:

\tan(x +  \frac{3\pi}{2} )  =  -   \cot \: x

One way is to use the basic double angle formula:

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{ \sin(x)  \cos( \frac{3\pi}{2} )  +   \cos(x)  \sin( \frac{3\pi}{2}) }{\cos(x)  \cos( \frac{3\pi}{2} )   -    \sin(x)  \sin( \frac{3\pi}{2}) }

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We simplify further to get:

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{ 0  -   \cos(x) }{0 +    \sin(x) }

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\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{- \cos(x) }{ \sin(x) }

This finally gives:

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  -  \cot(x)

6 0
3 years ago
.If the side of an equilateral triangle is 6cm, then the area of triangle is
Oksi-84 [34.3K]

Answer:

9\sqrt{3} cm^2

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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So, if x=28 1/3

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So, Length=51 2/3

4 0
2 years ago
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