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Anika [276]
3 years ago
13

Write the standard equation for the circle whose center is at ​(6​,2​) and whose radius is 2.

Mathematics
1 answer:
Grace [21]3 years ago
8 0

Answer:

(x - 6)^2 + (y - 2)^2 = 2^2.

Step-by-step explanation:

In general, let (a,\, b) denote the center of a given circle. Let r denote the radius of that circle. The standard equation for that circle would be:

(x - a)^2 + (y - b)^2 = r^2.

The circle in this question is centered at (6,\, 2).  

  • 6 is the x-coordinate of the center of this circle. a = 6.
  • 2 is the y-coordinate of the center of this circle. b = 2.

The radius of this circle is 2. Therefore, r = 2.

Hence, the standard equation for this circle would be:

(x - 6)^2 + (y - 2)^2 = 2^2.

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