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Vanyuwa [196]
3 years ago
9

What is the m Show work

Mathematics
1 answer:
Ghella [55]3 years ago
8 0

Answer:

measure of angle A is 80 degree.

Step-by-step explanation:

isosceles triangle will have same base angles

first base angle is 50, and the second will also be 50

3 angles of a triangle will add up to be 180 degree.

A is the vertex angle.

So 50 + 50 + A = 180

100 + A = 180

A = 80.

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Solve the simultaneous equations<br> 3<br> 2x - y = 7<br> xy = 15
ehidna [41]

Answer:

(5, 3 ) and (- \frac{3}{2}, - 10 )

Step-by-step explanation:

Given the 2 equations

2x - y = 7 → (1)

xy = 15 → (2)

Rearrange (1) expressing y in terms of x , that is

y = 2x - 7 → (3)

Substitute y = 2x - 7 into (2)

x(2x - 7) = 15

2x² - 7x = 15 ( subtract 15 from both sides )

2x² - 7x - 15 = 0 ← in standard form

(x - 5)(2x + 3) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 5 = 0 ⇒ x = 5

2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = - \frac{3}{2}

Substitute these values into (3) for corresponding values of y

x = 5 : y = 2(5) - 7 = 10 - 7 = 3 ⇒ (5, 3 )

x = - \frac{3}{2} : y = 2(- \frac{3}{2} ) - 7 = - 3 - 7 = - 10 ⇒ (- \frac{3}{2}, - 10 )

8 0
3 years ago
What is the additive inverse of t ? *
antiseptic1488 [7]

Answer:

-t

Step-by-step explanation:

Additive inverse of t:

t*-1 = -t

6 0
3 years ago
Read 2 more answers
What the answer plz help
ratelena [41]
20 = 40e^-0.1446t
e^-0.1446t = 0.5

t  = ln 0.5 / -0.1446
t =  4.8 days

4 0
3 years ago
Find sin X, sin Z, cos X, and cos Z. Write each answer as a simplified fraction.
just olya [345]

Answer:

Find the answers below

Step-by-step explanation:

Using m<X as the reference angle

Opposite YZ = 7

Adjacent  XY = 10

Hypotenuse XZ = √149

Using the SOH CAH TOA identity

sinX = opp/hyp

sinX =YZ/XZ

sinX = 7/√149

For cos X

cos X = adj/hyp

cos X =10/√149

Using m<Z as reference angle;

Opposite XY = 10

Adjacent  YZ = 7

Hypotenuse XZ = √149

Using the SOH CAH TOA identity

sinZ = opp/hyp

sinZ =10/√149

sinZ = 7/√149

For cos Z

cosZ = 7/√149

7 0
3 years ago
A firework is launched from the ground at a velocity of 180 feet per second. its height after t (t is variable) seconds is given
VMariaS [17]

-16t² + 180t

-16(2)² + 180(2)

-64 + 360

The fireworks height after 2 seconds is 296 feet

7 0
3 years ago
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