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andreyandreev [35.5K]
3 years ago
12

A coffee Merchant combines coffee costing $6 per pound with coffee costing $3.50 per pound how many pounds of each should be use

d to make a 25 lb of a blend costing $5.25 per pound
Mathematics
1 answer:
levacccp [35]3 years ago
3 0
\bf \begin{array}{lccclll}
&\stackrel{lb}{amount}&\stackrel{lb}{price}&\stackrel{total}{price}\\
&------&------&------\\
\textit{6 per lb coffee}&x&6&6x\\
\textit{3.5 per lb coffee}&y&3.5&3.5y\\
-------&------&------&------\\
mixture&25&5.25&131.25
\end{array}

same as before, we add the 1st and 3rd columns, since the mixture is just the sum of the elements above it.

\bf \begin{cases}
x+y=25\implies \boxed{y}=25-x\\
6x+3.5y=131.25\\
----------\\
6x+3.5\left( \boxed{25-x} \right)=131.25
\end{cases}
\\\\\\
6x+87.5-3.5x=131.25\implies 2.5x=131.25-87.5
\\\\\\
2.5x=43.75\implies x=\cfrac{43.75}{2.5}\implies x=17.5

how many lbs will it be of the 3.50 per lb coffee?  well, y = 25 -x.
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