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Anastaziya [24]

4 years ago

10

How code sould I use to make a robtic arm move

2 answers:

ahrayia [7]4 years ago

8 0

You may have to do your research online for this.

IRISSAK [1]4 years ago

4 0

adam use r/right/follow._10(inches)speed/2

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Extra points!!!!! <br><br> List the general types of housing<br> (Example: condo)

Nadusha1986 [10]

Answer:

co-op, apartment, townhome, manor etc

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3 years ago

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EastWind [94]

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3 years ago

3. An inductor is connected to a 60 Hz circuit. The inductive reactance is 75.42. What is the inductance of the

Digiron [165]

Answer:

Many circuits also contain capacitors and inductors, in addition to resistors and ... (a) Calculate the inductive reactance of a 3.00 mH inductor when 60.0 Hz and ... Part a of the figure shows a capacitor C connected across an A C voltage source V .... 5: (a) Find the current through a 0.500 H inductor connected to a 60.0 Hz, ...

Explanation:

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3 years ago

I WILL GIVE BRAINLIEST IF ANSWER FAST What is the measurement of this dial caliper?

Galina-37 [17]

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4 years ago

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A heat engine uses fuel of energy content 43.1 MJ/kg and produces 17.4 kW of useful power. The heat rejection rate (through the

solmaris [256]

Answer:

a)27.9%

b) $\dot{m}=3.06 \frac{Kg}{h}$

Explanation:

Given that

Fuel energy content = 73.1 MJ/kg

Useful power = 17.4 KW

Heat rejection rate = 44.8 KW

From first law of thermodynamics

Heat addition rate =Heat rejection rate + Power out put

Now by putting the values in the above formula

Heat addition rate = 44.8 + 17.4

Heat addition rate =62.2 KW

We know that efficiency is given as follows

$\eta =\dfrac{power\ out\ put}{Heat\ addition\ rate}$

So

$\eta =\dfrac{17.4}{62.2}$

$\eta =0.279$

So the efficiency is 27.9%.

Now to find usage rate of fuel

Lets take usage rate is $\dot{m}$

Fuel energy content x usage rate of fuel = Heat addition rate

Now by putting the values

$73100\times \dfrac{\dot{m}}{3600}=62.2$

$\dot{m}=3.06 \frac{Kg}{h}$

7 0

3 years ago