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3 years ago

Help plz (I GIVE VIRTUAL COOKIES)

Mathematics

1 answer:

Stolb23 [73]3 years ago

8 0

Answer: 45 90 135 215 315

1 2 3 5 7

Step-by-step explanation: not sure about the last one.

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Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

4 0

3 years ago

What is 624 divide by 27

mihalych1998 [28]

624/27

first you have to know what number that can be subtracted by 62

1. do 27 times 2 equal 54 then you subtract 62 by 54 equal 8 then you put 84 together that will 84 then multiply 27 times 3 = 81 then subtracted by 84

84-81 equal 3

In the calculator the answer is 23.1111111111

3 0

3 years ago

Jane was asked to find the factors of 8. Here is her work: 8 × 1 = 8 8 × 2 = 16 8 × 3 = 24 Factors of 8: 8, 16, 24 Which stateme

Maru [420]

Answer:

Jane found multiples of 8.

Jane should have gotten 1, 2, 4, 8 as her answer.

Step-by-step explanation:

Factors : 1,2,4,8.

1*8=8

2*4=8

4 0

3 years ago

three numbers are in an arithmetic progression. Their sum is 3 and the sum of their squares is 11. what are the three numbers

Vlad [161]

The three numbers are 12, 18 and 24

Arithmetic progression

Let the 3 number in arithmetic progression be:

a-d, d, a+d ...

If their sum is 3, then;

a-d+d+a+d = 3

2a + d = 3 ........... 1

If the sum of their squares is 11, then;

(a-d)² + d² + (a+d)² = 11

a²-2ad+d²+d²+a²+2ad+d² 11

2a²+3d² = 11 ....... 2

Solving the equations simultaneously, d = 6 and a = 12

First-term = 12

second term = 18

Thirs term = 24

Hence the three numbers are 12, 18 and 24

Hope this helps you!!!!!! :D

5 0

2 years ago

Read 2 more answers

Simplify the expression.<br> 3m - 3m<br> 3m - 3m =

uranmaximum [27]

3m-3m=0, simply by using 3-3 :)

3 0

3 years ago